Calculation ① 2 (x ^ 2) ^ 3 * x ^ 2-3 (x ^ 3) ^ 2 + 5x ^ 2 * x ^ 6 ② (- 2 ^ 2) * - 2) ^ 2

Calculation ① 2 (x ^ 2) ^ 3 * x ^ 2-3 (x ^ 3) ^ 2 + 5x ^ 2 * x ^ 6 ② (- 2 ^ 2) * - 2) ^ 2

2(x^2)^3*x^2-3(x^3)^2+5x^2*x^6
=2x^6*x^2-3x^6+5x^2*x^6
=2x^(6+2)-3x^6+5x^(2+6 )
=2x^8-3x^6+5x^8
=2x^8+5x^8-3x^6
=7x^8-3x^6
(-2^2)*(-2)^2
=-4*4
=-16

A simple method is used to calculate: 56 × 74 + 85 × 44 + 11 × 56

56×74+85×44+11×56，=56×（74+11）+85×44，=56×85+85×44，=（56+44）×85，=100×85，=8500．

How to calculate 3.5 * 17 0.9 simply

3.5*171-3.5*0.1=598.5-0.35=598.15

Given 1 + 2 + 3 + 4 + 5 +. = 17 * 33, calculate the value of 1-3 + 2-6 + 3-9 + 4-12 +. - 96 + 33-99

1-3+2-6+3-9+4-12+.-96+33-99
=(1+2+3+.+33)-3*(1+2+3+.+33)
=-2*(1+2+3+.+33)
=-2*17*33
=-1122

M * n = 3m-2n, calculated as (5 / 3 * 5 / 4) * 4 / 3

（5／3＊5／4）＊4／3=（5／3*3-5／4*2）＊4／3
=（5-5/2）＊4／3=5/2*4/3=5/2*3-4/3*2=7/2

If real numbers a, B, C satisfy a + B + C = O, ABC = 1. It is proved that at least one of a, B, C is not less than 2 / 3

Counter evidence
Let ABC be less than 2 / 3, because ABC = 1, so ABC must be 2 negative and 1 positive
If ABC is equal, let C > 0
So 0

As shown in the figure, there is a piece of land with a triangle. Now it is required to draw a line segment through a vertex of the triangle and divide its area equally into two parts. How do you think this line segment should be drawn______ Why______ ．

If the center line of a triangle divides the triangle into two triangles of equal area, the center line can be made through any point

Given that point P is a moving point on the parabola y square = 2x, the projection of point P on the Y axis is m, and the coordinates of point a are (7 / 2,4), then the minimum value of PA + PM is obtained

Simple, no points, detour
Do the intersection of the y-axis vertical line and the curve through a, that is, to get the smallest point P, the answer is 7 / 2
Give me a point

Factorization: 2a3-8a2 + 8A=______ ．

2a3-8a2 + 8a, = 2A (a2-4a + 4), = 2A (A-2) 2

As shown in the figure, in the isosceles trapezoid ABCD, AD / / BC, ab = CD, ab = AD + BC, P is the midpoint of ab
Ad is the upper sole, BC is the lower sole, AB is the left waist, DC is the right waist, P is the midpoint of ab

Because ABCD is trapezoid, AP = BP, CQ = DQ
So PQ / / AD / / BC
PQ=(AD+BC)/2
And ab = AD + BC
So PQ = AB / 2
AB=CD
PQ=CD/2
And because q is the midpoint of the CD side of △ CDP
So, DPC is a right angle