Simple calculation of 61 / 62 times 63

Simple calculation of 61 / 62 times 63

61 out of 62 times 63
=61/62*（62+1）
=61/62*62+61/62
=61+61/62
=61 and 61 / 62

In △ ABC, if Sina = 2cosbcosc, then tanb + Tanc=______ ．

Tanb + Tanc = sinbcosb + sinccosc = sinbcosc + cosbsinccosc = sin (B + C) cosbcosc = sin (π − a) cosbcosc = sinacos bcosc = 2, so the answer is: 2

I'd like some vegetables soup, too_______ some vegetables soup.

I'd like some vegetables soup, too__ also ____ ___ like____ some vegetables soup.

As shown in the figure, the side of the first square (let the side length be 2) is the hypotenuse of the first isosceles triangle, and the right side of the first isosceles right triangle is the second square
The side of the second square is the hypotenuse of the second isosceles right triangle... So we continue to connect. Through observation and research, please write the side length A2012 of the 2012 square as ()

This is very simple. I don't know what grade you are in. In fact, this problem is an application problem of equal ratio sequence. The side length of the first square is 2, the side length of the second square is root 2 (√ 2), the side length of the third square is 1 (), and the fourth is the reciprocal of (root 2). The proportion between the side lengths of each adjacent square is √ 2, so the first one is (√ 2) 2, The second is (√ 2) 1, the third is 0 times of radical 2, the fourth is - 1 times of radical 2, and so on. The general expression is an = (√ 2) 3-N
So the side length of Di 2012 square is A2012 = (√ 2) 3-2012 = (√ 2) - 2009 (root 2) negative 2009 times

What is the synonym of course in English? What is the third person singular of carry? What is the antonym of before? What is the antonym of free
Come on,

certainly
carries
after
busy

Who can tell me how to learn sine cosine theorem?
I'm not good at trigonometric function, but now I know about triangles. I can't help it

The first chapter of trigonometric function has the theorem in the blue box, that is, sine equals opposite side divided by hypotenuse, cosine equals adjacent side divided by hypotenuse, tangent equals opposite side divided by adjacent side

There are two verbs in an English sentence. Do you want to call the other verb ing
For example, if I can teach you to do beef noodles has two verbs, teach and do, do you want to add ing

There can only be one predicate verb in a sentence. Other verbs can have many forms, not necessarily ing, because it needs infinitives to express what has not happened, and what we are ready to do

What is the basic meaning of the law of demand in economics

In general, when the market price rises, the quantity of demand will decrease; when the market price falls, the quantity of demand will increase. According to the law of demand, if the price of demand is the vertical axis and the quantity of demand is the horizontal axis, then the demand curve is a right

The problem of complex number needs to be solved in the process
The set of complex Z suitable for the condition / Z / = 1, / (Z + 1) / (Z-1) / = 1

Let z = x + Yi
|z|^2 = 1
x^2 + y^2 = 1
(z+1)/(z-1)
=(x+1 + yi)/(x-1 + yi)
= (x+1+yi)(x-1 -yi)/[(x-1 + yi)(x-1 -yi)]
= [x^2 - (1+yi)^2]/[(x-1)^2 +y^2]
= [x^2 +y^2 - 2yi -1]/[x^2 + y^2 - 2x + 1]
Substitute x ^ 2 + y ^ 2 = 1 into the above formula
= (1 - 2yi -1)/(1 - 2x + 1)
= -2yi/(2 -2x)
= -yi/(1-x)
|(z+1)/(z-1)|^2 = 1
y^2/(1-x)^2 = 1
y^2 = (1-x)^2
simultaneous
y^2 = (1-x)^2
x^2 + y^2 = 1
1-x^2 = (1-x)^2
1-x^2 = 1 -2x + x^2
2x^2 - 2x = 0
x^2 -x = 0
x(x-1) = 0
X = 0 and x = 1
Substituting x ^ 2 + y ^ 2 = 1
Corresponding to y = ± 1 and y = 0 respectively
When x = 1, y = 0
The denominator of (Z + 1) / (Z-1) is 0, so it is rounded off
So the solution set of Z is {Z | z = ± I}

The difference between the parallel line property theorem on one side of triangle and the parallel line property theorem on one side of triangle

Theorem: parallel to the triangle on one side of the line cut the other two sides, cut the corresponding line proportional
Corollary: a line parallel to one side of a triangle cuts the lines of the other sides, and the corresponding line segment is proportional
The difference between the two is that the theorem itself is proportional to the line segments on both sides, while the inference is extended to the line where the edge is