When x takes what value, the algebraic formula (x-2004) ^ 2-2005 has the minimum value? What is the minimum value?

When x takes what value, the algebraic formula (x-2004) ^ 2-2005 has the minimum value? What is the minimum value?

When x is taken as 2004, it has the minimum value, which is - 2005

The minimum value of algebraic formula x-2004 + x-2005 +... + x-2009 + x-2010

X takes 2007 to get 12
x=12

|1 / 3-1 / 2 | + | 1 / 4-1 / 3 | + | 1 / 5-1 / 4 | +. + | 1 / 2005-1 / 2004 |?

1/3-1/2

The factorization result of the polynomial - 2x & # 178; + 2 + 4xy-2y & # 178; is

-2x²+2+4xy-2y²
=-2(x²-2xy+y²)
=-2(x-y)²

What is a 360 degree angle
it 's nothing

It's the corner
A ray revolves around its end point. When the beginning and end edges coincide completely, the angle formed is called circumference
1 circumference = 360 degrees
Circumference is the origin of 360 degrees

Finding the range of roots of equation 2x & # 179; + 3x-3 = 0

f(x)=2x³+3x-3
f'(x)=6x²+3>0
That is, the function is incremental
So the function has at most one real root
And f (0) = - 3
f(1)=2+3-3=2
f(0)f(1)

(10.5*11.7*57*85)÷(1.7*1.9*3*5*7*9*11*13)

=15/11=1.36363636.
Specific: molecular
10.5=7*1.5
11.7=9*1.3
57=1.9*30
85=1.7*50
So: the original formula = [(7 * 1.5) * (7 * 1.3) * (1.9 * 30) * (1.7 * 50)] / (1.7 * 1.9 * 3 * 5 * 7 * 9 * 11 * 13)
After approximately = 15 / 11
I'm laughing,

Find the limit of function y = (x-1) * (X-2) ^ 2 * (x-3) ^ 3 * (x-4) ^ 4 when x tends to positive infinity

Are you sure x tends to be positive infinity?
Obviously, when x goes to positive infinity,
X-1, (X-2) ^ 2, (x-3) ^ 3, (x-4) ^ 4 tend to be positive infinity,
that
Y = (x-1) * (X-2) ^ 2 * (x-3) ^ 3 * (x-4) ^ 4 also tends to be positive infinity

The simple calculation of 1-2-3 + 4-5 + 6-7 + 8-10 + 11 needs a process

1-2-3+4-5+6-7+8-10+11=(1+11)-(2+10)+(4+6)-(3+7)+8=8

Using factorization to do some calculation problems
1. (2x + y) square - (x + 2Y) square
2. Square of (a-b) + 4AB
3.3.14 times the square of 7.8 - 3.14 times the square of 1.1 times 4

Square of (2x + y) - (x + 2Y)
=[(2x+y)- (x+2y)][(2x+y)+ (x+2y)]
=(x-y)(3x+3y)
=3(x-y)(x+y)
(a-b)^2+4ab
=a^2-2ab+b^2+4ab
=a^2+2ab+b^2
=(a+b)^2
3.14*7.8^2- 3.14*1.1^2*4
=3.14*7.8^2- 3.14*2.2^2
=3.14*(7.8^2- 2.2^2)
=3.14*(7.8+2.2)*(7.8-2.2)
=3.14*10*5.6
=31.4*5.6
=175.84