For any real number x1, X2, min (x1, x2) denotes the smaller number in x1, X2, if f (x) = the square of 2-x, G (x) = x, find min [f (x), G (x)] and answer its maximum value

f(x)-g(x)
=2-x^2-x
=-(x^2+x-2)
=-(x+2)(x-1)
therefore
When - 2

For real numbers X1 and X2, min {x1, X1} is defined as the smaller number of X1 and x2. If the function y = 2 - (the square of x) and the function z = x, then the maximum value of Min {y, Z} is

Y1, or, X

Note that the minimum value of real number X1 and X2 is min {x1, X2}, for example, min {0, - 1} = - 1. When x takes any real number, the maximum value of Min {- x ^ 2 + 4,3x} is

1. Let f (x) = - X & # 178; + 4, G (x) = 3x2, the image of F (x), G (x) 3, the image of function min {- X & # 178; + 4,3x} be the lower part of these two images at the same place. 4. Combined with the function image, then the maximum value of Min {- X & # 178; + 4,3x} is that of these two functions at the

A is the midpoint of the de side of the triangle CDE, BC = 1 / 3CD. If the area of the triangle ABC is 6 square centimeters, find the s triangle CDE

Because a is the midpoint
So SCDA = 1 / 2scde
BC=1/3CD
So SABC = 1 / 3 SCDA
SCDA=3*6=18
SCDE=2*18=36

A mathematical method for finding the greatest common divisor and the least common multiple
16 and 28 (greatest common divisor and least common multiple)
16. 36 and 24 (least common multiple)

The greatest common divisor of 16 and 28 is 4 and the least common multiple is 112
16. The least common multiple of 36 and 24 is 144

It is proved that the ratio of the circumference of similar triangles is equal to that of similar triangles
96 property theorem 1: the ratio of height corresponding to similar triangles, the ratio of central line corresponding to similar triangles and the ratio of bisector of corresponding angles are equal to similar ratio
97 property theorem 2 the ratio of the circumference of similar triangles is equal to the similar ratio
Property theorem 3 the ratio of area of similar triangle is equal to the square of similar ratio

Let ABC and ABC be similar. A / a = B / b = C / C = x, X is the similar ratio. A = ax, B = BX, C = Cx. A + B + C = ax + BX + CX is deduced, then the ratio of circumference of similar triangle (a + B + C) / (a + B + C) = (AX + BX + Cx) / (a + B + C) = X

1、 The greatest common divisor of two positive integers is 6 and the least common multiple is 90
How many pairs are there in the first pair of large numbers composed of two positive integers of
1. How to find the greatest common divisor of two numbers
2. How to find the least common multiple of two numbers
3. The first pair of large numbers composed of two positive integers
4. Explain the problem in detail

Greatest common divisor, least common multiple
First, we decompose X and Y into prime factors
x=2^a·3^b·5^c… ,y=2^m·3^n ·5^p…
The greatest common divisor is the common and least degree prime factor of X and y
The least common multiple takes the common and largest prime factor of X and y, and then multiplies it by the uncommon prime factor
For example, find the greatest common divisor and the least common multiple of 12 and 30
12=2^2×3 ,30=2×3×5
The greatest common divisor = 2 × 3 = 6, the least common multiple = 2 ^ 2 × 3 × 5 = 60
(Note: for example, 2 ^ a means the power of 2 to the power of a, which is the representation in computer.)
90 = 2 × 2 × 3 × 5, 4,6,10,15,18,30,45,90 of the product combination. Because the greatest common divisor is 6, these two numbers must be multiples of 6, so only 6 and 18,30,90 of the combined number meet the condition. Assuming 6, only 90 of the condition is true. Assuming 18, only 30 of the condition is satisfied, so the two logarithms are (90,3) and (30,18)

If L1 is perpendicular to L2, then the slope of L2 is? If L1 is parallel to L2, then the slope of L2 is?

0 the second slope does not exist

This is a pear

These are pears

The image of a function y = - 2x + 1 passes through the vertex of parabola y = x2 + MX + 1 (M is not equal to 0), and the value of M is obtained

The vertex of parabola y = x2 + MX + 1 is (- M / 2,1-m ^ 2 / 4)
So m + 1 = 1-m ^ 2 / 4, m ^ 2 + 4m = 0
So m = - 4

For any real number x1, X2, min (x1, x2) denotes the smaller number in x1, X2, if f (x) = the square of 2-x, G (x) = x, find min [f (x), G (x)] and answer its maximum value