Let f (x) = 2sinx / 4, then for any x ∈ R, f (x1) ≤ f (x) ≤ f (x2), then the minimum value of x1-x2 is ()

Let f (x) = 2sinx / 4, then for any x ∈ R, f (x1) ≤ f (x) ≤ f (x2), then the minimum value of x1-x2 is ()

For any x ∈ R, f (x1) ≤ f (x) ≤ f (x2), so f (x1) = Fmin (x), f (x2) = Fmax (x) and - 1 ≤ SiNx / 4 ≤ 1, so f (x1) = - 2, X1 = 8N π - 2 π, n is an integer, f (x2) = 2, X2 = 8m π + 2 π, M is an integer, x1-x2 = 4 π + 8 (m-n) π, obviously the minimum value is 4 π

For any real number x1, X2, min {x1, X2}, denote the smaller number in x1, X2, if f (x) = 2-x2, G (x) = x, f (x) = min {f (x), G (x)}, then the maximum value of F (x) is______ ．

Let f (x) = g (x), that is, 2-x2 = x, the solution is x = - 2, x = 1. From the meaning of the question, f (x) = min {f (x), G (x)} = 2 − X2, X ＜− 2x, − 2 ≤ x ≤ 12 − X2, x > 1. From the image, f (x) max = f (1) = 1. So the maximum value of F (x) is 1. So the answer is: 1

It is known that the line L passes through the point m (1,3) and the inclination angle is π / 3. The parameter equation of circle C is x = 1 + 5cos θ y = 5sin θ (t is the parameter)
Line L and circle C intersect at P1 and P2, and find the distance between P1 and P2

Solving the equation Y-3 = Tan π / 3 (x-1) of line L
That is y = √ 3x - √ 3 + 3
The parameter equation of circle C is x = 1 + 5cos θ y = 5sin θ
Know (x-1) ^ 2 + y ^ 2 = 25
The center of the circle is (1,0) and the radius is 5
The distance from the center of the circle (1,0) to the straight line y = √ 3x - √ 3 + 3
d=/3//√1^2+(√3)^2=3/2
It is also known from the vertical diameter theorem
(1/2P1P2)^2+d^2=r^2
Namely
(1/2P1P2)^2+9/4=25
That is, (1 / 2p1p2) ^ 2 = 91 / 4
That is, 1 / 2p1p2 = √ 91 / 2
That is, p1p2 = √ 91

9x + 1.25-5x = 0.5 to solve the equation

9x+1.25-5x=0.5
The result is: 9x-5x = 0.5-1.25
If we combine the similar items, we can get 4x = - 3 / 4
Divide both sides by 4 to get x = - 3 / 16

Let m = {(x, y) x = y = 1, x, y belong to R} n = {(x, y) X-Y, 0, XY belong to R} then the number of elements in M intersection n of sets

Let m = {(x, y) | x = y = 1, x, y belong to R} n = {(x, y) | X-Y = 0, x, y belong to R} then the number of elements in the intersection n of M
Set M = {(1, - 1), (1,1), (- 1,1) (- 1, - 1)}
Set n is actually a parabola (y = x)
In the set M, only (1,1), (- 1,1) are on the parabola y = X
So the number of elements in M intersection n is 2

Simple calculation of 9 * (- 110 has 11 out of 10 13)
*It's a ride

Original form
＝9×（－111＋2/13）
＝-999+18/13
= - 999 + (1 and 5 / 13)
= (997 and 8 / 13)

(1) if the distance between a and B is D, what is the quantitative relationship between D and m, n
(2) If it is known that the numbers represented by a and B on the number axis are x and - 1, then the distance d between a and B can be expressed as____ If d = 3, find X

(1) D = im -- Ni. The distance between two points on the number axis is equal to the absolute value of the difference of their coordinates
(2) The distance d between a and B can be expressed as d = IX + 1I
If d = 3, then IX + 1I = 3,
X + 1 = 3 or x + 1 = -- 3
So x = 2 or x = -- 4

5 and 2 1-2 and 20 13-2.35 1 and 8 5 + 2 and 6 1 + 1.375 + 4 and 6 5
Two simple problems

1. The original formula = 5.5-2.65-2.35 = 5.5 - (2.65 + 2.35) = 5.5-5 = 0.5
2. The original formula = (1.625 + 1.375) + (1 / 2 + 4 / 6) = 3 + 7 = 10

Given that the odd function f (x) defined on (1, - 1) is a decreasing function in the domain of definition, and f (1-A) + F (1-2a) > 0, the range of real number a is obtained
Given that the odd function f (x) defined on (1, - 1) is a decreasing function in the domain of definition, and f (1-A) + F (1-2a) > 0, the range of real number a is obtained

Since f (x) is an odd function, f (- x) = - f (x)
So f (1-A) + F (1-2a) > 0, that is f (1-A) > - f (1-2a) = f (2a-1)
F (x) decreases monotonically on (- 1,1), so
1-a2/3
-1

How do 8 and 2 and 4 and 6 equal 24

4×8-2-6=24