It is known that f (x) is an odd function and G (x) is an even function. When x ≥ 0, f (x) = LG (x + 1); when x < 0, G (x) = f (x), the analytic expression of G (x) when x > 0 is obtained

It is known that f (x) is an odd function and G (x) is an even function. When x ≥ 0, f (x) = LG (x + 1); when x < 0, G (x) = f (x), the analytic expression of G (x) when x > 0 is obtained

F (x) is an odd function and G (x) is an even function
There are
f(-x)=-f(x)
g(-x)=g(x)
Let x > 0, then - X

The even function F X defined on R increases monotonically from [0 to positive infinity], and F 1

The even function f (x) on R increases on [0, + ∞),
f(1)

It is known that the function FX is an even function with two periods, and when x belongs to 0 to 1, FX = x + 1, then the analytic expression of the function from 1 to 2 is

X ∈ (1,2), then X-2 ∈ (- 1,0) even function, f (x) = f (X-2) = f (2-x) = 2-x + 1 = x + 1

Given that FX = (x + a) (x + 1) is an even function, find the value of A

General form of quadratic function and variable vertex form
Y = - 1 / 4x ^ 2-x + 3. Y = a (X-H) ^ 2 + K
Learning steps. Process

General formula: y = ax & sup2; + BX + C
Vertex formula: y = a (x + B / 2a) & sup2; + (4ac-b & sup2;) / 4A
The above formula should be changed to y = - 0.25 (x + 2) & sup2; + 4
-(it's basic knowledge. It's in math textbooks. It's not a skill. Just memorize it by rote.)

The square of (x + 2) - 25 = 0

(x+2)^2-25=0
(x+2)^2=25
x+2=+-5
X = 3 or - 7

Cut a piece of circular paper into the largest square. The diameter of the circle is 6cm

Find the area of the circle: 6 / 2 = 3cm, 3.14 * 3 square = 28.26cm, find the area of the square, the square is composed of two triangles, area: 6 * 3 / 2 = 9cm, 9 * 2 = 18cm, 28.26-18 = 10.26cm

As shown in the figure, the image with inverse scale function y = K / X (x is greater than zero) passes through the rectangle
 

Let:; (a, b), then a (a, 0), B (0, b), m (1 / 2a, 1 / 2b) because m is the intersection of diagonal of rectangular oabc. Since m is on y = K / x, k = 1 / 4AB. Because e is on y = K / x, e (K / B, b) so s △ OCE = 1 / 2oC × CE = 1 / 2K, the same as D (a, K / a), so s △ oad = 1 / 2K, so s quadrilateral odbe = s

Calculate with the definition of partial derivative!

A × 3 and 3 / 5 = B × 1 = C × 5 / 9, and a, B, C are not equal to 0
A. The order of B and C

A × 3 and 3 / 5 = B × 1 = C × 5 / 9, and a, B, C are not equal to 0. Please arrange the order of a, B, C from small to large
(1) A, B and C are all less than 0
C