Factorize the following formulas: ① 16x^2-49y^2 ② 4+12(x-y)+9(x-y)^2 ③ x^3-9x ④ a^4-2a^2 b^2+b^4 ⑤ (a^2-a)^2-(a-1)^2 ⑥ 16x^4-1 Fill in the blanks: ① 3^2004 -4*3^2003 +10*3^2002=_______ ② 3^n+2 -4*3^n+1 +10*3^n=_______ There is also a question about factoring 16-(2a+3b)^2

Factorize the following formulas: ① 16x^2-49y^2 ② 4+12(x-y)+9(x-y)^2 ③ x^3-9x ④ a^4-2a^2 b^2+b^4 ⑤ (a^2-a)^2-(a-1)^2 ⑥ 16x^4-1 Fill in the blanks: ① 3^2004 -4*3^2003 +10*3^2002=_______ ② 3^n+2 -4*3^n+1 +10*3^n=_______ There is also a question about factoring 16-(2a+3b)^2

① 16x^2-49y^2
=(4x+7y)(4x-7y)
② 4+12(x-y)+9(x-y)^2
=(3x-3y+2)
③ x^3-9x
=x(x^2-9)
=x(x+3)(x-3)
④ a^4-2a^2 b^2+b^4
=(a^2-b^2)^2
=[(a+b)(a-b)]^2
=(a+b)^2(a-b)^2
⑤ (a^2-a)^2-(a-1)^2
=[a(a-1)]^2-(a-1)^2
=a^2(a-1)^2-(a-1)^2
=(a-1)^2(a^2-1)
=(a-1)^2(a+1)(a-1)
=(a-1)^3(a+1)
⑥ 16x^4-1
=(4x^2+1)(4x^2-1)
=(4x^2+1)(2x+1)(2x-1)
① 3^2004 -4*3^2003 +10*3^2002=_______
=3^2002(3^2-4*3^1+10)
=3^2002(9-12+10)
=7*3^2002
② 3^n+2 -4*3^n+1 +10*3^n=_______
=3^n(9-12+10)
=7*3^n

Given 3A + 7b = 4b-3, if the value of a + B is required, how should it be deformed? What is the value of a + B?

3a+7b=4b-3
3a+3b=-3
3(a+b)=-3
a+b=-1

If the line ax + 2Y + 6 = 0 is perpendicular to the line x-a (a + 1) y + (a-squared-1) = 0, find the value of A

The slope of the line ax + 2Y + 6 = 0 is - A / 2
The slope of the line x-a (a + 1) y + (a squared-1) = 0 is 1 / a (a + 1)
Because the two lines are perpendicular
So (- A / 2) [1 / a (a + 1)] = - 1
2(a+1)=1
a=-1/2

When a =?, the system of equations 3x + ay x-4y has a unique solution

3x+ay=6 （1）
x-4y=0 （2）
Substituting (2) into (1) yields (a + 12) y = 6
When a = - 12, the equation has no solution
When a#12, the equation y = 6 / (a + 12) x = 4Y = 24 / (a + 12)
In this case, the equations have unique solutions
If you are satisfied, take it

The ratio of a to B is 0.6, so the ratio of a to B is (). A.3:5 b.0:6 c.5:3

A

Find the range of (x ^ 2-9) under the function y = 6-radical

Because x ^ 2-9 is greater than or equal to 0 under the root sign, the range is negative infinity to 6

Given that a = 8 / 3, B = 7 / 4, find the value of / A / + / B /?

/a/+/b/
=(8/3)+(7/4)
=(32/12)+(21/12)
=53/12

If the image of the function y = ax + 2 and y = BX + 3 is compared with a point on the x-axis, then what is a: B equal to?

Take y = 0, two formulas are obtained: x = - 2 / A, x = - 3 / b
Because the intersection on the X axis is: - 2 / a = = - 3 / B,
a：b=2：3

If the distance from a point P on the parabola y & # 178; = x to the collimator is equal to the distance from it to the vertex, the coordinate of point P is?

Let P (x, y), from y ^ 2 = x = 2 * (1 / 2) X -- > the focal coordinate be (1 / 4,0), and the Quasilinear equation x = - 1 / 4
The distance from a point P to the directrix is equal to the distance from it to the vertex -- > x ^ 2, y ^ 2 = [x - (- 1 / 4)] ^ 2, substituting y ^ 2 = X
We get x = 1 / 8
y^2=1/8
So p is (1 / 8, 4 / 2) and (1 / 8, negative 4 / 2)

In 1 / 3 x + 1 = 7, the value of X is ()
a.18 b.6 c.9

a
The solution is x = 18