How many pieces of rectangular iron pieces, 90cm long and 42cm wide, should be cut into square iron pieces with the same area and the same number of centimeters, if there is no surplus?

How many pieces of rectangular iron pieces, 90cm long and 42cm wide, should be cut into square iron pieces with the same area and the same number of centimeters, if there is no surplus?

The greatest common factor of 90 and 42 is 6
So it can be cut into a square with a side length of 6 cm
90 / 6 * 42 / 6 = 15 * 7 = 105 pieces

The length of 90 cm, 42 cm wide rectangular row of iron cut into a whole centimeter, square iron area are equal, just no surplus
How many pieces can you cut at least?
105 is the right answer. No, go away.

90=6×15
42=6×7
At least = 15 × 7 = 105 pieces

How many pieces of iron sheet can be cut from a rectangular iron sheet 42 cm wide and 90 cm long into a small square iron sheet with the length of the whole centimeter and the same area (no surplus)?

The greatest common divisor of 90 and 42 is 6, that is to say, the side length of the small square is 6cm, then the number of blocks that can be cut in length: 90 △ 6 = 15 (blocks), the number of rows that can be cut in width: 42 △ 6 = 7 (rows), the total number of blocks that can be cut: 15 × 7 = 105 (blocks); a: at least 105 blocks

If you cut a rectangular piece of iron 108 cm long and 72 cm wide into a square piece of iron with the same side length and area, and there is no surplus, you should cut at least () pieces

(108,72)=36
（108÷36）×（72÷36）
=3×2
=6 (pieces)

How many pieces can be processed at least when a rectangular iron block 90 cm in length and 35 cm in width is processed into the largest square iron piece with the same area and the length of the whole centimeter, and there is no surplus?

The greatest common divisor of 90 35 is 5
At least (90 ﹣ 5) x (35 ﹣ 5) = 18x7 = 126 pieces
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As shown in the picture, a rectangular cardboard with a length of 5cm and a width of 2cm, a rectangular cardboard with a length of 4cm and a width of 1cm, a square cardboard and two other rectangular cardboard just form a big square. What's the area of the big square? (unit: cm)

Suppose the side length of a small square is x, then the side length of a large square is 4 + (5-x) cm or (x + 1 + 2) cm. According to the meaning of the question, we get: 4 + (5-x) = (x + 1 + 2), and the solution is: x = 3, 4 + (5-x) = 6, and the area of a large square is 36 square centimeters. Answer: the area of a large square is 36 square centimeters

What is the area and volume of a rectangular paperboard with a length of 8cm and a width of 5cm, which is rotated along its long side for one circle?

The figure is a cylinder, the height of the cylinder = the length of the rectangle = 8 cm, the bottom radius of the cylinder = width = 5 cm
Area of cylinder bottom = 3.14 × 5 & # 178; = 78.5 (cm2)
Side area = 3.14 × 5 × 2 × 8 = 251.2 (cm2)
Surface area = 251.2 + 78.5 × 2 = 408.2 (cm2)
Volume = 78.5 × 8 = 628 (cm3)

Take a rectangular paperboard with the ratio of length to width of 5:2, cut off four small squares with side length of 5cm, and use it to make a rectangular packing box without cover. To make the volume of the packing box 200cm ^ 3 (the thickness of the paperboard is ignored), what are the length and width of the rectangular paperboard?

Suppose the length of this rectangular paperboard is 5x and the width is 2x, then
5（2x-10)(5x-10)=200
The solution, x = 1 (rounding off), x = 6
Therefore, the length of this rectangular cardboard is 5x = 30, and the width is 2x = 12

1. There is a rectangular paperboard, 18 cm long and 15 cm wide. Cut the paperboard into small squares of the same size without surplus. What is the maximum area of each small square? How many pieces can it be cut into?
2. Wear three pieces of iron wire with the length of 12 meters, 18 meters and 30 meters into the same sections. There is no surplus of the three pieces of iron wire. How long is the maximum length of each section? How many sections can be formed?
3. A batch of bricks, 45 cm long and 30 cm wide, at least how many bricks can be used to make a square?

The greatest common factor of 1.18 and 15 is 3, so the maximum side length of small square is 3 cm, and the area is 3 × 3 = 9 cm;
18 △ 3 = 6 15 △ 3 = 5 can be cut into 6 × 5 = 30 (pieces)
The greatest common factor of 2.12, 18 and 30 is 6 12 △ 6 = 2 18 △ 6 = 3 30 △ 6 = 5
Each section is up to 6 meters long, and can be cut into (2 + 3 + 5) = 10 sections
3. A batch of bricks, 45 cm long and 30 cm wide, at least how many bricks can be used to make a square?
The least common multiple of 45 and 30 is 90 ﹣ 45 = 2, 90 ﹣ 30 = 3
2 × 3 = 6, at least 6 pieces

A rectangular board, 60 cm in length and 24 cm in width, if the cardboard is built into several squares of the same size, and no surplus is allowed
At least how many squares can be cut into

The greatest common divisor of 60 and 24 is 12, so the side length of a square is 12 cm
(60÷12)×(24÷12)
=5×2
=10
A: at least cut them into 10 squares with a side length of 12 cm