The arcuate area formula can calculate the arcuate area when the chord length and height are known 1. Chord length 8.5, height 0.075, arch area? 2, chord length 8.5, height 0.095, arch area? 2? 3. Chord length 11.5, height 0.075, arcuate area? 4, chord length 11.5, height 0.095, arcuate area?

Let the arc of arc AB be arc ab,
Then:
When the arc AB is a inferior arc, then s arc = s sector - s △ AOB (a, B are the ends of the arc, O is the center of the circle)
If the arc AB is a semicircle, then s arc = s sector = 1 / 2S circle = 1 / 2 × π R ^
When the arc AB is a superior arc, then s arc = s sector + s △ AOB (A and B are the ends of the arc, O is the center of the circle)
The calculation formulas are as follows:
S＝nπR^2/360－ah/2
S＝πR^2/2
S = n π R ^ 2 / 360 + ah / 2 (n is radian, R is radius, a is chord length, h is height of triangle)
Arc of excellence
An arc larger than a semicircle is called a superior arc
Three letters are used to represent a superior arc (example: arc Mon)
Bad arc
An arc smaller than a semicircle
An arc less than 180 degrees
An arc less than π
Here, we need the radius and radian of the circle where the bow is located, and we also need to find it according to the Pythagorean theorem

When the chord length is 50 meters and the chord height is 6.5 meters, the radius and arc length can be calculated

Given chord length L = 50m, chord height h = 6.5m, calculate radius R and arc length C?
The center angle is a
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=6.5/2+50^2/(8*6.5)
=51.327m
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((50/2)/51.327)
=58.3 degrees
=58.3*PI/180
=1.01747 radians
C=A*R
=1.01747*51.327
=52.224m

How to get the formula of cone side area
How to get the formula of cone side area?

The side view of a cone is a sector. A sector is a part of a circle with the same radius as it. First, measure the center angle (angle) of the sector, n = the center angle, the surface area of the cone = the side area of the cone + the bottom area of the cone. Divide the center angle by 360 degrees (written as a fraction) times the square of π r plus the square of π R, s = n / 360

Volume and area formula of cone
For example, what are the volume and area of a cone with a height of 6cm, a radius of 1cm, a diameter of 2cm?

Conic volume formula v = 1 / 3 × s × HS is the bottom area = π × R × RH is high, π is the circumference, that is 3.14, R is the bottom radius surface area formula s surface = s bottom area + s side area the side area of conic is a fan after expansion, so: s side area = π × R × L, R is the bottom radius, l is the bus length

The area formula of cone

The question is the surface area of the cone:
Open the side area of the cone as a sector, and the radius of the sector is the generatrix
Surface area = bottom area + side area
Surface area = s = π * R ^ 2 + π Rl (L is the bus length)

If there is a 5cm chord in a circle with a radius of 5cm, the distance from the midpoint of the chord to the midpoint of the inferior arc is

There is a 5cm chord in a 5cm radius circle
Then the two radii and the chord form an equilateral triangle
The distance from the center of the circle to the middle of the chord is 5 * 60
The distance from the midpoint of the string to the midpoint of the inferior arc is 5-5sin60 = 5-5 √ 3 / 2

If the radius of the circle is 2cm and the length of a chord in the circle is 23cm, then the distance from the midpoint of the chord to the midpoint of the inferior arc opposite to the chord is______ cm．

According to the vertical diameter theorem, half of the chord is 3cm, and then according to the Pythagorean theorem, the distance between the chord center and the inferior arc is 1cm, then the distance between the chord center and the inferior arc is 2-1 = 1cm

Arc length 24, chord length 20, find the distance from the midpoint of the chord to the arc

Arc length C = 24, chord length L = 20, find the distance h from the midpoint of the chord to the arc?
The radius of arc is r, and the center angle of arc is a
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=12
R1=11.667
R2=11.687
R3=11.688
R4=11.688
R = 11.688m
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((20/2)/11.688)
=117.647 degrees
H=R-R*COS(A/2)
=11.688-11.688*COS(117.647/2)
=5.637m

A broken wheel is shown in the figure. The distance between the two ends of the remaining arc is a = 0.72M, and the distance from the middle point of the arc to the chord of the arc is h = 0.25m
If a wheel of the same size needs to be machined, what is the radius of the wheel?

If the broken wheel is less than half a wheel, let its center be o, its two ends be a and B, and the middle point of arc AB be c. connect OA, OC, OC to ab at D. according to the vertical diameter theorem, OC bisects AB and OC ⊥ AB, so ∠ ODA = 90, ad = 0.36, CD = 0.25, let OA = OC = R. according to the Pythagorean theorem, (r-0.25) & sup2; + 0.36 & sup2; =

If the radius of circle O is 8cm and the length of chord AB is 8cm, then the distance from the midpoint of chord AB to the midpoint of arc AB,

The distance from the midpoint of chord AB to the midpoint of arc AB d = 8 - √ (8 & # 178; - 4 & # 178;) = 8-4 √ 3 (CM)

The arcuate area formula can calculate the arcuate area when the chord length and height are known 1. Chord length 8.5, height 0.075, arch area? 2, chord length 8.5, height 0.095, arch area? 2? 3. Chord length 11.5, height 0.075, arcuate area? 4, chord length 11.5, height 0.095, arcuate area?