The length and width of a rectangle are two different prime numbers. The perimeter of the rectangle is 56 cm. What is the maximum area of the rectangle?

28 = the sum of the lengths of two adjacent sides. 28 = 3 + 25.28 = 5 + 23.28 = 7 + 21.28 = 11 + 17.28 = 13 + 15.28 = 19 + 9. No more. Only 11 times 17 is the maximum. This is a common arithmetic method. If you use algebra, you can set the area as S. one side is x, and the adjacent side is (28-x). S = x * (28-x)

The perimeter of a rectangle is 40 cm. Its length and width are composed of a prime number and a composite number. What is the maximum possible area? What is the minimum possible area?

Maximum 11 * 9 = 99
Minimum 2 * 18 = 36

The perimeter of a rectangle is 198 decimeters, and the length and width are prime numbers. The length, width and area of the rectangle are very small

Length + width = 99 meters, length and width are prime numbers, so length = 97, width = 2, area = 197 square centimeters

The perimeter of a rectangle is 16, and its length and width are prime numbers. Try to find the area of the rectangle

7 or 15

The circumference of a rectangle is 120 meters, and its length is 1.5 times of its width. What is the area of the rectangle?

Width: 120 / [(1 + 1.5) * 2] = 120 / 5 = 24
Length: 24 * 1.5 = 36, area of rectangle = 24 * 36

The perimeter of a rectangle is 120cm, and the ratio of length to width is 7:5. The area of the rectangle is______ Square centimeter

7 + 5 = 12 (copies), 120 △ 2 × 712 = 60 × 712 = 35 (CM); 120 △ 2 × 512 = 60 × 512 = 25 (CM); 35 × 25 = 875 (square cm); answer: the area of this rectangle is 875 square cm. So the answer is: 875

The perimeter of a quadrilateral is 48CM. It is known that the first side is a & nbsp; cm, the second side is 3cm longer than twice the first side, and the third side is equal to the sum of the first and second sides. (1) write the formula for the length of the fourth side; (2) when a = 3cm or a = 7cm, can you still get a quadrilateral? What shape is the figure at this time?

(1) ∵ the first side length is ACM, according to the meaning of the title: the second side length is (2a + 3) cm, the third side length is (a + 2A + 3) cm, and the perimeter of the quadrilateral is 48CM, ∵ the fourth side length is: 48-a - (2a + 3) - (3a + 3), = 48-a-2a-3-3a-3, = 42-6a (CM); (2) when a = 3, the edges of the four sides

The perimeter of a quadrilateral is 48CM. It is known that the first side is a & nbsp; cm, the second side is 3cm longer than twice the first side, and the third side is equal to the sum of the first and second sides. (1) write the formula for the length of the fourth side; (2) when a = 3cm or a = 7cm, can you still get a quadrilateral? What shape is the figure at this time?

(1) ∵ the first side length is ACM, according to the meaning of the title: the second side length is (2a + 3) cm, the third side is (a + 2A + 3) cm, and the perimeter of the quadrilateral is 48CM, ∵ the fourth side length is: 48-a - (2a + 3) - (3a + 3), = 48-a-2a-3-3a-3, = 42-6a (CM); (2) when a = 3, the side lengths of the four sides are 3, 9, 12, 24 respectively, because 3 + 9 + 12 = 24. It is not a quadrilateral. It is a line When a = 7, the lengths of the four sides are 7, 17, 24 and 0 respectively. Obviously, it is not a quadrilateral. It is still a line segment. Answer: the length of the fourth side is (42-6a) cm. When a = 3cm or a = 7cm, the quadrilateral can not be obtained. It is a line segment

The perimeter of a quadrilateral is 48CM. It is known that the length of the first side is ACM, and the length of the second side is 2cm less than 3 times of the length of the first side. Then the length of the third side is equal to the sum of the lengths of the first side and the second side?

The length of the fourth side
= 48 -a - (3a-2) - (a+3a-2)
= 48 -a - 3a +2 - a -3a +2
= 48 -8a +4
= 44 -8a

It is known that the perimeter of a quadrilateral is 48CM, the first side is ACM, the second side is 3cm more than twice of the first side, and the third side is equal to the first and second sides
(1) Write the formula for the fourth side length;
(2) If the fourth side length is 18cm, find a

The fourth side length = 48-2 (a + 2A + 3)
If the fourth side length is 18cm
48-2(a+2a+3)=18
3a+3=15
a=4

The length and width of a rectangle are two different prime numbers. The perimeter of the rectangle is 56 cm. What is the maximum area of the rectangle?