When m is the value, the univariate quadratic equation x ^ 2 + (2m-3) x + (m ^ 2-3) = 0 Why the value of M has two real roots

(1) When the equation is a quadratic equation of one variable, the coefficient of the quadratic term of the equation should be ≠ 0, and the rest of the terms are ignored, then m-2 ≠ 0, n takes all the real numbers to get m ≠ 2, and N is all the real numbers (2)

Factorization factor 25 (M + N + 2) ^ 2-16 (m-n-2) ^ 2

25(m+n+2)²-16(m-n-2)²
=[5(m+n+2)+4(m-n-2)][5(m+n+2)-4(m-n-2]
=(9m+n+2)(m+9n+18)

R = 5.6 r = 1.4 π R & sup2; - π R & sup2; please use the square difference formula (π is about 3.14)

π R & sup2; - π R & sup2; = Wu (R ^ 2-r ^ 2) = Wu (R + R) (R-R) = Wu * 7 * 4.2
=29.4 μ = 92.316

Extracting common factor -- square difference formula method
(1)(x+y)^3(x-y)-(x+y)(x-y)^3
(2)25(x-2y)^3+4(2y-x)

Question 1 (x + y) ^ 3 (X-Y) - (x + y) (X-Y) ^ 3 = (x + y) (X-Y) [(x + y) ^ 2 - (X-Y) ^ 2] = (x ^ 2-y ^ 2) (x ^ 2 + 2XY + y ^ 2-x ^ 2 + 2xy-y ^ 2) = 4xy (x + y) (X-Y) question 225 (x-2y) ^ 3 + 4 (2y-x) = 25 (x-2y) ^ 3-4 (x-2y) = (x-2y) [25 (x-2y) ^ 2-4] = (x-2y) [5 (x-2y) + 2] [5 (

How many geometric argumentation methods are there for square difference formula?

1. Algebra
2. Operation with letters: (a + b) (a-b) = a2-ab + ab-b2 = A2-B2

(M + n) ^ 2-N ^ 2 factorization with square difference formula

(m+n)^2-n^2
=(m+n+n)(m+n-n)
=m(m+2n)

(M + N-B) (m-n + b) is calculated by the square difference formula

(m+n-b)(m-n+b)
=【m+（n-b)】【(m-（n-b)】
=m²-（n-b)²
=m²-n²+2nb-b²

(M + n) (m-n) square difference formula calculation
*
(m+n)(m-n)

(m+n)(m-n) = m²-n²

If (xy-x + 1) (XY + x-1) = m ^ 2-N ^ 2, then n =?
Mathematics problems in grade two of junior high school

N=x-1

How to prove the square difference formula?
Party A - Party B

(a + b) (a-b) is expanded by the law of multiplicative distribution, and the formula of square difference is obtained

When m is the value, the univariate quadratic equation x ^ 2 + (2m-3) x + (m ^ 2-3) = 0 Why the value of M has two real roots