Ask for help in math. About factorization （a+b）2(a-b)+（a-b）2（a+b） （x+y）2-4y2 （m+2n）2+2(m+2n)(2m+n)+(2m+n)2 x2+2xy+y2-4x-4y-5 a4-a2-72 x2-3x3-9+27x

Ask for help in math. About factorization （a+b）2(a-b)+（a-b）2（a+b） （x+y）2-4y2 （m+2n）2+2(m+2n)(2m+n)+(2m+n)2 x2+2xy+y2-4x-4y-5 a4-a2-72 x2-3x3-9+27x

(a + b) 2 (a-b) + (a-b) 2 (a + b) (x + y) 2-4y2 = (x + y) ^ 2 - (2Y) ^ 2 = (x + y + 2Y) (x + y-2y) = (x + 3Y) (X-Y) (M + 2n) 2 + 2 (M + 2n) (2m + n) + (2m + n) 2 = (M + 2n + 2m + n) ^ 2, complete square = (3m + 3n) ^ 2 = 9 (M + n) ^ 2x2 + 2XY + y2-4x-4y-5 = (x ^ 2 + 2XY + y ^ 2) - (4x + 4Y) -

1.（1-1/2²）（1-1/3²）······（1-1/9²）（1-1/10²）
2.100²-99²+98²-97²+······+2²-1
3. (12th power of 10 + 25) - (12th power of 10-25) = nth power of 10

1.
=(1-1/2)(1+1/2) (1-1/3)(1+1/3) .(1-1/10)(1+1/10)
=1/2 * 3/2 * 2/3 *4/3 *3/4*.9/10*11/10
=1/2*11/10
=11/20
2.100²-99²+98²-97²+······+2²-1
=(100-99)(100+99) + (98-97)*(98+97) +.(2-1)(2+1)
=100+99+98+97+...+2+1
=101*100/2
=5050
3. (12th power of 10 + 25) - (12th power of 10 - 25) = nth power of 10
(12th power of 10 + 25) - (12th power of 10-25) = 12th power of 10 + 12th power of 25-10 + 25 = 50

How to write these questions about factorization?
m(x-y)²-x+y
If a & sup2; (B-C) + B & sup2; (C-A) + C & sup2; (a-b) = 0, prove that at least two of the three numbers a, B and C are equal
(c²-a²-b²)²-4a²b²

m(x-y)²-x+y=m(x-y)(x-y)-(x-y)=(x-y)(mx-my-1)a²(b-c)+b²(c-a)+c²(a-b)=a²b-a²c+b²(c-a)+ac²-bc²=b(a²-c²)+ac(c-a)+b²(c-a)=ac(c-a)+b²(c-a)-b(...

[1] The square of X-6 [2] the cubic-2y of 50y

(1)x^2-x-6
=(x-3)*(x=2)
(2)50y^3-2y
=2y*(5y-1)*(5y+1)