A cube box, the edge length is 16. How many square decimeters does the box cover?

A cube box, the edge length is 16. How many square decimeters does the box cover?

It's 16.5 × 16.5 = 272.25 square decimeters

To make a rectangular box with a volume of 369 square centimeters, a height of 6cm and a bottom surface of 5cm longer than the width, what should be the length and width of the bottom surface?

The volume is 369 square centimeters, the volume is 369 square centimeters, the height is 6cm, and the bottom area is 369 / 6 = 61.5
That is to say, length multiplied by width is 61 and 2 / 3
Because the length is 5cm more than the width
Let the width be X
X（X+5）=61.5
Using the root formula of quadratic equation of one variable, we can get that x is about 5.7, so the width is 5.7 and the length is 10.7

To make a rectangular box with a volume of 750cm3, a height of 6cm and a bottom length 5cm more than the width, what should be the length and width of the bottom (accurate to 0.1cm)?

Suppose the width of the bottom of the cuboid is xcm, then the length is (x + 5) cm
The result is: x2 + 5x-125 = 0
When x = 9.0, x + 17 = 26.0, x + 12 = 21.0
A: you can choose a rectangular sheet of iron with a width of 21cm and a length of 26cm

To make a cuboid box with a volume of 1500cm3, a height of 10cm, and a length 5cm more than a width of the ground, calculate the length and width of the ground

Let the width of the ground be ACM, then a * (a + 5) * 10 = 1500,
A = 10 cm, 10 + 5 = 15 cm,
So the ground is 15cm long and 10cm wide

Make the image of the function y = - 2x + 4, write out the coordinates of the intersection a and B of the image and the horizontal and vertical axis, and calculate the area of the triangle AOB determined by the origin o of the AB coordinate

Y = - 2x + 4, intersection with horizontal axis (2,0), intersection with vertical axis (0,4)
The area of the triangle surrounded by the coordinate axis is: 2 * 4 / 2 = 4

Find the area of the triangle formed by two intersections a B of the straight line y = 1 / 3x + 2 and hyperbola x2 / 9 - Y2 / 4 and the origin

Let a (x1, Y1), B (X2, Y2)
Take y = 1 / 3x + 2 into x ^ 2 / 9 - y ^ 2 / 4 = 1 to get
x^2-4x-24=0
x1+x2=4,x1x2=-24
AB=√(1+1/9)√(x1+x2)^2-4x1x2=4√70/3
The distance from the origin to the line y = 1 / 3x + 2 is 3 √ 10 / 5
Area of triangle 4 √ 7

The parabola y = 3x & sup2 intersects with the straight line y = - 5x + 2 at two points a and B, and O is the origin of the coordinate. What is the area of △ AOB?

Two simultaneous equations, 3x & sup2; = - 5x + 2, so x = - 2 or x = 1 / 3, so a (- 2,12), B (1 / 3,1 / 3), and the intersection of y = - 5x + 2 and Y axis is C (0,2), so the area of △ AOB is △ AOC + △ BOC = 2 * 1 / 3 divided by 2 + 2 * 2 divided by 2 = 7 / 3, so the area is equal to 7 / 3

If the area of the triangle formed by the image of the first-order function y = - 2x + B and the two coordinate axes is 9, then B=______ ．

The intersection coordinates of the line y = - 2x + B and the X axis are (B2, 0), and the intersection coordinates of the line y axis are (0, b). According to the area of the triangle is 9, we get 12 | B2 | · | B | = 9, that is, B24 = 9, and the solution is m = ± 6. So the answer is: ± 6

The intersection of the line y = - 2x + 1 and the X axis is___ The point of intersection with the y-axis is___ What is the area of the triangle enclosed by the two axes___ .

The area of triangle intersecting with X axis at (0.5,0) and Y axis at (0,1) is (1 * 0.5) / 2 = 0.25

The coordinate of the intersection of the line y = 2x-3 / 5 and the Y axis is, the coordinate of the X axis is, and the area of the triangle enclosed by the two axes is?

The intersection coordinates of the line y = 2x-3 / 5 and the Y axis are (0, - 3 / 5)
The coordinate of intersection point with X axis is (3 / 10,0)
The area of the triangle formed by these two points and the coordinate axis = (3 / 5) × (3 / 10) △ 2 = 9 / 100