Given f (x) = x & # 178; - x + 43, the real number a satisfies | x-a|

Given f (x) = x & # 178; - x + 43, the real number a satisfies | x-a|

Take a into f (x) to get: F (a) = a ^ 2-A + 43
So f (x) - f (a) = x ^ 2-x + 43-A ^ 2 + a-43 = x ^ 2-A ^ 2-x + a = (x + a) (x-a) - (x-a) = (x-a) (x + A-1)
|f(x)-f(a)|=|(x-a)(x+a-1)|=|x-a||x+a-1|

A mathematical problem about inequality in Senior Two
The function f (x) is a monotone decreasing odd function with the domain R. it solves the inequality f (m * 2 ^ x) + F (2 ^ x-4 ^ x-1) (M is a constant)
It's knocked out, followed by > 0

If we transfer the term, we get f (m * 2 ^ x) > - f (2 ^ x-4 ^ x-1),
So f (m * 2 ^ x) > F (4 ^ X-2 ^ x + 1)
And because of monotone decreasing, m * 2 ^ X

The inequality part!
It is known that ABCD satisfies the following three conditions simultaneously
（1）d＞c（2）a＋b=c＋d（3）a＋d＜b＋c
Compare the size of ABCD and state the reason
Thank you very much~

The solution is a + B = C + D
a＋d＜b＋c
So a + B + A + D