Given the function f (x) = log a ^ (x ^ 2-2x + 3) (a is greater than 0, a is not 1), when a belongs to [0,3], f (x) is greater than - 1, find the value range of real number a A is the base. Find the value range of A
When a belongs to [0,3], it should be "when x ∈ [0,3]". If f (x) = log a ^ (x 178; - 2x + 3) x 178; - 2x + 3 = (x-1) 178; + 2 > 0, let u = x 178; - 2x + 3, then f (x) = log a ^ u x ∈ [0,3] 2 ≤ u ≤ 6
If loga 3 / 4 is less than 1 (a is greater than 0, and a is not equal to 1), find the value range of real number a
When a > 1
Y = loga x is monotonically increasing on (0, infinity) and y = loga 3 / 4 < 1 when x = 1 and Y1
When 0
If (loga3 / 4) &;
(loga3/4)^2
If the real number a satisfies loga (2) > 1, then the value range of a is
loga(2)>1
That is, loga (2) > loga (a)
If 0