For example, there are two points a (1,0) and B (- 1,0) on the plane of the graph, and the known equation of the circle is (x-3) ^ 2 + (y-4) ^ 2 = 2 ^ 2 Find the maximum area of ABP1 with a point p1 on the circle and find out the area

For example, there are two points a (1,0) and B (- 1,0) on the plane of the graph, and the known equation of the circle is (x-3) ^ 2 + (y-4) ^ 2 = 2 ^ 2 Find the maximum area of ABP1 with a point p1 on the circle and find out the area

P1 (3,6), maximum area 6
Details are as follows:
The equation of circle is (x-3) ^ 2 + (y-4) ^ 2 = 2 ^ 2
That is, the circle with (3,4) as the center and 2 as the radius
Calculate the maximum area of ABP1, that is, when the ordinate of P1 is the maximum
The maximum ordinate of P1 is 6
ABP1 area is 2 * 6 / 2 = 6

There are two points a (- 1,0) and B (1,0) in the plane
Point P in the circle (x-3) square plus (y-4) square = 4. Find the coordinates of P when the square of AP plus the least square of BP
Help, square will not use symbols, on the Chinese characters, please help

When this point is (x, y), AP ^ 2 + BP ^ 2 = (x + 1) ^ 2 + y ^ 2 + (x-1) ^ 2 + y ^ 2 = 2x ^ 2 + 2Y ^ 2 + 2 becomes twice the distance from the point on the circle to the origin plus 2 to connect the center of the circle and the origin (the straight line is y = 4 / 3x). The intersection circle meets the above conditions at (9 / 5,12 / 5) and (21 / 5,28 / 5) (9 / 5,12 / 5)