There are two points a (- 1,0) and B (1,0) on the plane, and point P is on the circle (x-3) 2 + (y-4) 2 = 4. Find ap2 There are two points a (- 1,0), B (1,0) on the plane, and point P is on the circle (x-3) 2 + (y-4) 2 = 4. Find the coordinates of point P when ap2 + bp2 takes the minimum value The equation of a circle is that the square of (x-3) plus the square of (y-4) equals 4 [2 is the square] What we need is also the square of AP plus the square of BP

There are two points a (- 1,0) and B (1,0) on the plane, and point P is on the circle (x-3) 2 + (y-4) 2 = 4. Find ap2 There are two points a (- 1,0), B (1,0) on the plane, and point P is on the circle (x-3) 2 + (y-4) 2 = 4. Find the coordinates of point P when ap2 + bp2 takes the minimum value The equation of a circle is that the square of (x-3) plus the square of (y-4) equals 4 [2 is the square] What we need is also the square of AP plus the square of BP

The coordinates of P point coordinates are (m, n), then AP (AP) \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\origin (0

In the plane rectangular coordinate system known by senior one mathematics, point O is the origin, a (- 3, - 4) B (5, - 12)
Why can coordinates be multiplied directly

I don't know what question you are asking, but there is a formula (a, b) * (C, d) = AC + BD, which is the vector knowledge of senior one

In the plane rectangular coordinate system, the point P is different from the origin. Now we connect the points P and rotate it three times anticlockwise around the origin
The corresponding points P1, P2 and P3 were obtained by rotating 90 ° each time
If the coordinates of P are (3,1), write the coordinates of P1P2P3 and calculate the area of the quadrilateral pp1pp4
Generally, if the coordinates of point P are (a, b), please write the coordinates of P1P2P3 and calculate the area of quadrilateral pp1pp3

If the angle of counterclockwise rotation around the origin is θ, the relationship between the corresponding point coordinates (x ', y') and the original coordinates (x, y) is as follows:
x'=xcosθ-ysinθ
y'=xsinθ+ycosθ
Rotate 90 ° and substitute into the formula to get P1 (- 1,3)
Rotate 180 ° to get P2 (- 3, - 1)
Rotate 270 ° to get P3 (1, - 3)
It is easy to prove that pp1pp3 is a square, the area formula is s = C & # / 2, and C is the diagonal length
The distance between two points is 2 √ 10, so the area is 20
P(a,b)
Then P1 (- B, a), P2 (- A, - b), P3 (B, - a)
S=[2√(a²+b²)]²/2=2(a²+b²)

On plane rectangular coordinate system
If the distance from point P to X axis is 2, and the distance from point P to y axis is 3, and it is in the fourth quadrant, then the coordinate of point P is——

(3,-2)
The distance to the horizontal axis is the absolute value of the ordinate, the distance to the vertical axis is the absolute value of the abscissa, and the fourth quadrant is positive and negative, so it is (3, - 2)