Using factorization to solve equation -- X ^ 2 + y ^ 2-2x + 4Y + 5 = 0

Using factorization to solve equation -- X ^ 2 + y ^ 2-2x + 4Y + 5 = 0

x^2+y^2-2x+4y+1+4=0
(x^2-2x+1)+(y^2+4y+4)=0
(x-1)^2+(y+2)^2=0
x-1=0
x=1
y+2=0
y=-2

4Y (Y-5) - 56 = 0 factorization solution equation

A:
4y(y-5)-56=0
y(y-5)-14=0
y^2-5y-2*7=0
(y-7)(y+2)=0
y1=7,y2=-2

Solving equation (y + 2) (Y-1) = 4 by factorization

(y+2)(y-1)=4
y^2+y-2=4
y^2+y-6=0
(y+3)(y-2)=0
y1=-3 y2=2

Factorization to solve equation -- X ^ 2 + y ^ 2-2x + 4Y = 0

Take the method of matching
x^2-2x+y^2+4y=0
(x-1)^2+(y+2)^2=5
The image is a circle with the center of point (1, - 2) and the radius of root 5

Solving equations 1200 + 4Y = 500X and 2400 + 20x = 20Y
（1）1200+4Y=500X
(2) 2400+20X=20Y
The solution is: X ≈ 3.39
Y≈123.39

Approximate points
300+y=125x (1)
120+x=y (2)
(2) Substituting (1)
300+120+x=125x
124x=420
x=420÷124≈3.39
y=120+x≈123.39

Solving the equation 4y-1 / 4 = 1 / 4Y + 1

4y-1 / 4 = 1 / 4Y + 1 both sides multiply by 4 at the same time
16Y-1=Y+4
16Y-Y=4+1
15Y=5
Y=1/3

3 (y-4) - 2 (4y-3) > 3 (Y-8)

3(y-4)-2(4y-3)18/8
y>9/4
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To solve the equation of first order with three variables 5x + y + Z = 1 2x-y + 2Z = 1 x + 5y-z = - 4, the second equation of first order with three variables X: y = 2:1 Y: z = 2:1 x + y-3z = 6

Make it simple. Do you understand
The first Formula 1 + 2 is 7x + 3Z = 2 (formula 4)
Formula 2 multiplied by 5 is 10x-5y + 10z = 5 (formula 5)
Formula 5 + 3 is 11x + 9z = 1 (formula 6)
Formula 4 and formula 6 give x = 1 / 2 and z = - 1 / 2
Substituting x, Z to 2 gives y = - 1
The second one is x = 2Y, y = 2Z
X=4Z
Substitute the above formula into x + y-3z = 6
4Z+2Z-3Z=6
Z=2
So x = 8, y = 4

Solve the linear equation of three variables: x + y-5z = 16, y + z-5x = 4, Z + x-5y = - 14

x+y-5z=16 (1)
y+z-5x=4 (2)
z+x-5y=-14 (3)
(1)+(2)+(3)
-3(x+y+z)=6
x+y+z=-2 (4)
(4)-(2)
6x=-6 x=-1
(4)-(3)
6y=12 y=2
(4)-(1)
6z=-18 z=-3
x=-1 y=2 z=-3

Solving equations 2x-5y = 9 5x + 4Y = 6

2x-5y=9
5x+4y=6
8x-20y=36
25x+20y=30
33x=66
x=2
4-5y=9
5y=-5
y=-1
x=2
y=-1