Square of 2002 + square of 2002 * square of 2003 + square of 2003 = a, it is proved that a is the complete square root

Square of 2002 + square of 2002 * square of 2003 + square of 2003 = a, it is proved that a is the complete square root


Proof: because a = 2000 ^ 2 + 2002 ^ 2 * 2003 ^ 2 + 2003 ^ 2
=2002^2+2003^2-2*2002^2003+200^2*2003^2+2*2002*2003+1-1
=(2003-2002)^2-1+(2002*2003+1)^2
=1-1+(2002*2003+1)^2
=(2002*2003+1)^2
So a is the complete square root