If the square root of (x + 2) is positive or negative 2, then the arithmetic square root of 2x + 5 is?

If the square root of (x + 2) is positive or negative 2, then the arithmetic square root of 2x + 5 is?

The arithmetic square root of x = 2, 2x + 5 is 3

If the two square roots of an integer are 3a-5 and 2a-6, find the number

There are two square roots of a number, which are opposite to each other
(3a－5)＋(2a－6)=0
5a=11
a=11/5
Then:
3a－5=(33/5)－5=8/5
Then the number is (8 / 5) &# 178; = 64 / 25

Given that m and N are real numbers, under the root sign (9-3m) + 2, under the root sign (M-3) = n + 1, find the square root of m-n

√(9-3m)+2√(m-3)=n+1
9-3m>0,9-3m=0
m0,m-3=0
m>3,m=3
So only m = 3
√(9-3m)+2√(m-3)=n+1
0+0=n+1
n=-1
m-n=0-(-1)=1
√m-n=√1=±1

We know the quadratic equation of one variable MX ^ 2 - (m ^ 2 + 2) x + 2m = 0 about X. if this equation has two integer roots, find the value of M

The equation has two integer roots, so m ≠ 0
Factorization
(mx-2)(x-m)=0
x=2/m,x=m
M is an integer and M is a factor of 2
M is ± 1, ± 2