Given that an original function of F (x) is (SiNx) ln x, find ∫ (π, 1) XF '(x) DX

Given that an original function of F (x) is (SiNx) ln x, find ∫ (π, 1) XF '(x) DX

f(x)=(sinxlnx)'=cosxlnx+sinx/x
The original formula = ∫ (π, 1) XDF (x)
=xf(x)(π,1)-∫(π,1)f(x)xdx
=x(cosxlnx+sinx/x)(π,1)-sinxlnx(π,1)
=-πlnπ-sin1

The image of the function FX = ln (x2 + 1) is approximately

X = 0 is the () discontinuity of the function f (x) = 1 / 1-2 ^ X

I'm glad to answer for you
The answer is: infinite discontinuities
Because the left and right limits of F (x) do not exist
If you have any questions, please ask~

The function f (x) = X-1 / x ^ 2-x has infinite discontinuities x =? Has removable discontinuities x =?

X = 0 and x = 1 are infinite discontinuities

When Xiao Fei did the calculation of multiplying two digits by two digits, he regarded the fourth on the 34th digit of the second factor as 9. The result is 55 more than the correct product. What is the correct result?
We need to work out the formula

55÷（9-4）=11
11×34=374

When doing the calculation of two digit numbers, we regard the 4 on the second factor 34 as 9, and the result is 55 more than the correct product. What is the correct result?

The first factor
=55/（9-4）
=55/5
=11
The correct result is 11 * 34 = 374

In the calculation of multiplication of two digits by two digits, Xiao Mahu regarded 2 of the second factor 22 as 5, and the result was 69 more than the correct product

If 2 is regarded as 5, the factor increases by 5-2 = 3
More than 69
So the other factor is 69 / 3 = 23
22×23=506
A: the correct result is 506

When calculating the multiplication of two digit numbers by two digit numbers, Xiao Mahu wrote the error of 2 on the bits of a factor 22 as 5. The incorrect product is more than 69. What is the correct result?

The factor is 5-2 = 3
More than 69
So the other factor is 69 △ 3 = 23
The correct product is 23 × 22 = 506

In the calculation of multiplying two digits by two digits, Congcong regarded 2 of 22 digits of the second factor as 5, and the result was 69 more than the correct product

69÷(5-2)x22=506
The correct result should be 506

When calculating the multiplication of two digits by two digits, Congcong regarded the 2 on the 22 bits of the second factor as 5, and the result was 69 more than the correct product. What should be the correct product

If 2 is regarded as 5, the result is 69 more than the correct product, which shows that the first factor is 69 (5-2) = 23, and the correct product should be 23 × 22 = 506