What is the difference between the binomial coefficient of binomial expansion and that of binomial expansion

The binomial coefficient is just C, and the coefficient is C multiplied by the power of the constant

In the (x + y) ^ 12 expansion, the term with the largest binomial coefficient is?

Item 7, x ^ 6y ^ 6
The coefficient is 12 * 11 * 10 * 9 * 8 * 7 / (6 * 5 * 4 * 3 * 2 * 1) = 924

The continuous interval of function f (x) = (X-6) / (x ^ 2-4x-12) is_ The break point is__ ?

f(x)=(x-6)/(x^2-4x-12)=(x-6)/(x-6)(x+2)
The continuous interval of function f (x) = (X-6) / (x ^ 2-4x-12) is (- infinity, - 2) ∪ (- 2, + infinity) and the discontinuous point is x = - 2

Let f (x) be continuous in the interval [- 1,1], then x = 0 is the ()
A. Jump discontinuity B. removable discontinuity C. infinite D. oscillation

Limx → 0 + G (x) = limx → 0 + ∫ x0f (T) DTX = limx → 0 + F (x), limx → 0 − g (x) = limx → 0 − ∫ x0f (T) DTX = limx → 0 − f (x); since f (x) is continuous in [- 1, 1], limx → 0 + F (x) = limx → 0 − f (x) = f (0), limx → 0 + G (x) = limx → 0 − g (x) = f (...)

Find the discontinuous point of the function and explain the type y = 1 / ln|x + 1|

X tends to 0, y tends to infinity, so x = 0 is an infinite discontinuity, belonging to the second kind of discontinuity

Continuity of functions of higher numbers
The following functions are discontinuous at the points indicated, indicating which type these discontinuous points belong to. If it is a removable discontinuity, supplement or change the definition of the function to make it continuous
（1）y=x/tanx,x=kπ,x=kπ+π/2(k=0,+ -1,+ -2,.)
(2)y=[cos(1/x)]^2,x=0

(1) Y = x / TaNx, k = 0, x = k π are removable discontinuities, y | x = 0 = 1, K ≠ 0, x = k π are the second type of discontinuities. X = k π + π / 2 are removable discontinuities, y | x = k π + π / 2 = 0
(2) Y = [cos (1 / x)] ^ 2, x = 0, is the second kind of discontinuity

The continuity of two functions
It is known that f (x) is continuous at x0 and G (x) is discontinuous at x0. Then what is the continuity of the functions obtained by adding, subtracting, multiplying and dividing g (x) respectively

The continuity of F (x) multiplication and division of G (x) at x0 is uncertain. The continuity of F (x) multiplication and division of G (x) at x0 does not depend on whether f (x) is 0 at x0, whether the limit of G (x) exists at x0, and whether it is bounded

Continuous partial high numbers of functions
1. The domain of the function f (x) = lgx / X-2 + arcsinx / 3 is as follows:
Among the following functions, the function bounded on the interval (0,1) is: () a, y = 1 / x, by = lgx, cy = e to the x power, D, y = 1 / SiNx
In the following functions, a y = 3-sin squared x b y = 2cos squared X-1 c y = a + TaNx d y = 1 + cos π / 2x

1.x/(x-2)>0
x> 2 or X

On the problem of removable discontinuities of functions in higher numbers
The removable discontinuity of function y = (x ^ 2-4) / (x ^ 2-3x + 2) is

= =

Ask for a question about the discontinuity of function in (Higher Mathematics)
F (x) = LIM (n →∞) [n times of X / [1 + (n times of x) + (2n times of 2x)]
（x> =0）,
Then this function:
a. There is no breakpoint
b. There is a breakpoint of the first kind
c. There are more than two first type discontinuities
d. There are more than two breakpoints
I've been doing this for a long time, and I think f (x) = 0, so the function f (x) is continuous. I choose a, but the answer is B,
So I hope the respondent
It's best to find the expression of F (x). If you don't need to find f (x), you can also simply talk about the idea of solving the problem. After thinking about it for a long time, you are depressed~
Squallnickey: but you seem to be wrong. It should be f (x) = 1 / (4a + 1 + 1 / a) and then a = 1 / 2
But if we substitute 1 / 2 into the original function, that is, f (x) = Lim [1 / [2 ^ (n + 1) + 1]] = 0
I still can't figure that out.

(Revised)
I don't care what's under the separation line
Well, a function like ax + B / x will have a break point at x = √ ab
For the function in your question, the value at that point is constant
Not affected by limit
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It should be like this:
F(x)=1/(2A + 1 + 1/A)
Where a = x ^ n
So what about
2A + 1 + 1 / A, when n → inf, there will be a break point when a = 1 / √ 2
(because 2A = 1 / A, f (x) = 1 / (2 √ 2 + 1), this point holds for all n)

What is the difference between the binomial coefficient of binomial expansion and that of binomial expansion