The following is a right triangle, with ab as the axis to rotate around it for a circle, get a three-dimensional figure, its volume is how many cubic centimeters?

The following is a right triangle, with ab as the axis to rotate around it for a circle, get a three-dimensional figure, its volume is how many cubic centimeters?

13 × 3.14 × 62 × 8 = 3.14 × 12 × 8 = 301.44 cubic centimeter; a: its volume is 301.44 cubic centimeter

The three sides of a right triangle are 3, 4 and 5 respectively. If the triangle is rotated one circle with the hypotenuse as the axis, what is the volume of the rotating body?
It's urgent. Hurry up!

An object that rotates on a bevel axis is
Circle with hypotenuse as diameter
The longest side of a right triangle is the hypotenuse of a right triangle L = 5
S circle area = π R ^ 2
R = half L = 2.5
So s = 2.5 square π
π=3.1415926...
I'll figure it out for myself
S=6.25π

Three sides of a right triangle are 3, 4 and 5. Rotate one circle around the hypotenuse axis to calculate the volume of the body of rotation

By rotating one circle with the bevel as the axis, two conical bodies with the same base are obtained
The bottom radius of the cone is the height of the hypotenuse of the right triangle: 3 * 4 / 5 = 12 / 5
According to Pythagorean theorem, the heights corresponding to the two cones are 16 / 5 and 9 / 5 respectively
According to the volume formula of cone: v = bottom area * height / 3;
The volume of rotator v = V1 + V2 = 1 / 3 (π 144 / 25) * 16 / 5 + 1 / 3 (π 144 / 25) * 9 / 5 = 48 π / 5

It is known that the two right sides of a right triangle are 15 cm and 20 cm respectively. Take its hypotenuse as the axis of rotation and rotate for one circle, the body of rotation is obtained. The volume of the body of rotation is calculated

According to the Pythagorean theorem, the length of the hypotenuse is ab = 25, the height is CD = 12, and the triangle turns around the hypotenuse to form two cones with the same base. The base is a circle, so the semi meridian is r = H = 12, and the area of the circle is s = Pai * R ^ 2 = 144 * Pai