As shown in the figure, in the plane rectangular coordinate system, point O is the coordinate origin, the edge of rectangle ABCD falls on the coordinate axis, a (0,3), C (4,0), and point F is a moving point on the line BC. (there are four questions in total. The fourth question is to compare the length of OE and of and find the original question.)

As shown in the figure, in the plane rectangular coordinate system, point O is the coordinate origin, the edge of rectangle ABCD falls on the coordinate axis, a (0,3), C (4,0), and point F is a moving point on the line BC. (there are four questions in total. The fourth question is to compare the length of OE and of and find the original question.)

According to the meaning of the title, the coordinate of point D is (5,0), OD = 5, PE is made through point P, perpendicular to the x-axis at point E, and point P moves on the edge of BC, so PE = 3, △ ODP is an isosceles triangle with waist length of 5
(1) When PD = od = 5, according to Pythagorean theorem, if ed ^ 2 = PD ^ 2-PE ^ 2 = 25-9 = 16, ed = 4, then OE = od-ed = 1, that is, the coordinate of point E is (1,0), so the coordinate of point P is (1,3);
(2) When Po = od = 5, according to Pythagorean theorem, OE ^ 2 = Po ^ 2-PE ^ 2 = 25-9 = 16, OE = 4, that is, the coordinate of point E is (4,0), so the coordinate of point P is (4,3)

1. What's the distance between Wang Ying and a when he walks 100 meters from a to B, and then 200 meters from B to C
2. Where is the point with equal distance to two intersecting straight lines? A is a straight line, B is a ray, C is two perpendicular lines
If a straight line edge equals half of the hypotenuse in a right angled trigonal, then the edge of the right angled edge equals half of the hypotenuse, and the acute angle of the right angled edge equals 30 degrees, is it a true proposition?... if so, please prove it
4. Is it true that the central line of a right angle side and another right angle side correspond to two equal 3-angle congruences? If so, please prove it
Explain the reason

1 by question: connect AC
Because the angle ABC = 60 degrees
BC=2AC
Naturally there is a triangle ABC, which is a right triangle with the angle BAC as the right angle
AC=√3AB=100√3(m)
The angle bisector of 2 a can satisfy that the distance between two intersecting straight lines is equal, and because it is a straight line, the angle bisector is also a straight line
Let's take a look at the question, "then what is the meaning of" the side opposite this right angle side "? Two" De's ", and the side can also be opposite?
4. Reason: if there is an explanation that it is a right angle and two lines are equal, we can naturally get the congruence of the rectangle surrounded by the middle lines of two right angle sides in two triangles. We also know that it is the middle line, so there are two right angle sides that are equal and there is no lack of a right angle, which is obviously congruent

In the isosceles trapezoid ABCD, AB / / CD, the diagonal AC is perpendicular to point P, there is a point Q on PD, connecting CQ, passing through point P as PE, perpendicular CQ, crossing CQ to point s, crossing DC to point E, taking EF = de on DC, passing through point F as FH, perpendicular CQ, crossing CQ to point t, crossing PC to point h. When point Q moves on Pd (not coincident with points P and D), does PQ of pH change? If it changes, find out the range of change; if it does not change, find out its value

Make BH ⊥ CD intersect at point m (1) ∵ a, the coordinates are (0,8), ⊥ OA = 8 = BM ∵ BC = 10, BM ⊥ CD, ⊥ cm = √ (BC ^ - BM ^) = 6 ∵ trapezoid, ABCD is isosceles trapezoid, OA ⊥ CD, ⊥ AOD ≌ BMC, ≌ od = cm = 6 ∵ points c and D are on the x-axis, and it can be seen from the figure that point D is located on the negative half axis of x-axis, and the coordinates of ⊥ D are (- 6,0) (2

As shown in the figure, AB is the diameter of ⊙ o, ab = 10cm, if the chord CD = 8cm, then the sum of the distances from points a and B to the straight line CD is ()
A. 12cmB. 8cmC. 6cmD. 4cm

Make og ⊥ EF, connect OD, ∵ o is the midpoint of AB, ∵ G is the midpoint of CD, ∵ og is the median line of rectangular aefb, ∵ og = AE + BF2, ∵ CD = 8cm, ∵ DG = 12CD = 4cm, ∵ AB = 10cm,