If the positive integer solution of inequality 3x-a ≤ 0 is 1, 2, 3, then the value range of a is 1______ ．

If the positive integer solution of inequality 3x-a ≤ 0 is 1, 2, 3, then the value range of a is 1______ ．

If we solve the inequality 3x-a ≤ 0, we can get x ≤ A3. The positive integer solution of ∵ inequality is 1, 2, 3, 3 ≤ A3 < 4, and the solution is 9 ≤ a < 12. So the answer is: 9 ≤ a < 12

We know that the inequality 3x is suitable for one variable

3x

It is known that mx-m1 is an inequality of one degree with respect to X;

The solution set of (M + 3) x < m + 3 is x > 1
∴m+3＜0
∴m＜-3

If the inequality about X (│ m │ - 1) x's square + (m-1) x + 1 ＞ 0 is a linear inequality of one variable, then (M = - 1),
Why does the teacher say "M-1 = 0" during the lecture?

∵ (| m | - 1) x & # 178; + (m-1) x + 1 ＞ 0 is a linear inequality of one variable
So there is no quadratic term and the coefficient of the first term is not 0
That is | m | - 1 = 0, M-1 ≠ 0
The solution is: M = ± 1, m ≠ 1
∴m＝－1

If inequality 3 (x-1) ≤ MX square + nx-3 is a one variable linear inequality about X, find the value of M and n

By combining the similar items, we can get
MX ^ 2 + (n-3) x > = 0
M = 0, n is not equal to 3

If x is less than or equal to m + 1, and X is greater than 2m-1, there is no solution

If x is less than or equal to m + 1 and X is greater than 2m-1, there is no solution
So there are
m+1

If the system of linear inequalities with one variable x minus two m greater than zero x plus m less than 2 has a solution, then what is the range of M

If the solution set of the system of linear inequalities with one variable x > M-1 x > m + 2 is x > - 1, can you find the value range of M?

∵(m+2)-(m-1)=3>0
m+2>m-1
∴x>m+2
X > - 1
∴m+2≤-1
M ≤ - 3

If the solution set of linear inequality system x > M-1 x > m + 2 is x > - 1, then the value range of M can be obtained

Solution
x>-1
x> M-1 is M-1

2 (x + 1) - 3 (X-2) > 8
Another problem is the system of equations, {3x-2 (5-3x) > 8,2x ≤ 2 (2x + 3)

2(x+1)-3(x-2)>8
2x+2-3x+6>8
-x>0
x8①
2x≤2(2x+3)②
The results are as follows
3x-10+6x>8
9x>18
x>2
It is concluded from (2)
2x≤4x+6
-2x≤6
x≥-3
In conclusion, the solution set of inequality system is x > 2