Given the line l1:3x + 4Y = 6 and l2:3x-4y = - 6, then the relationship between the inclination angles of line L1 and L2 is

Given the line l1:3x + 4Y = 6 and l2:3x-4y = - 6, then the relationship between the inclination angles of line L1 and L2 is

k1=-3/4,k2=3/4
If the numbers are opposite to each other, the two lines are symmetric about the y-axis
Inclination angle relation ∠ 1 + ∠ 2 = 180 degree

Find the equation of the line which is parallel to the line l1:3x + 4y-5 = 0 and whose distance from L1 is 1 / 10

Let the linear equation be: 3x + 4Y + C = 0, and use the distance formula of parallel straight line = | C1-C2 | / √ (a ^ 2 + B ^ 2),
|c+5|/√(3^2+4^2)=1/10
|c+5|/5=1/10
|c+5|=1/2
C = - 4.5 or C = - 5.5
The equation of the line which is parallel to the line l1:3x + 4y-5 = 0 and whose distance from L1 is 1 / 10 is as follows:
3x+4y-4.5=0 ,
3x+4y-5.5=0

The equation of a line passing through point (1,2) and perpendicular to the line 3x + 4Y + 17 = 0 is?

Let the line be y = KX + B
Perpendicular to the line 3x + 4Y + 17 = 0
The slope of the line is k = - 1 / (- 3 / 4) = 4 / 3
Passing point (1,2)
SO 2 = 4 / 3 * 1 + B
b=2/3
y=4/3x+2/3
That is 4x-3y + 2 = 0