Let F: X → - x ^ 2 be the mapping from real number set M to real number set n. if there is no original image in M for real number P ∈ n, then the value range of P is

Let F: X → - x ^ 2 be the mapping from real number set M to real number set n. if there is no original image in M for real number P ∈ n, then the value range of P is

The mapping f: X → - x ^ 2 is the mapping from real number set M to real number set n
In essence, it is a function whose domain of definition is m and range of value is {f (x)}. It is a subset of N and a subset of non positive real number set
So for the real number P ∈ n, there is no prime image in M,
The range of P is (0, + ∞)

Let F: X → - X & # 178; + 2x be the mapping from real number set M to real number set n. if the real number P belongs to N, there is no primitive image of P in M
Try to determine the value range of P

y=-x²+2x=-(x-1)²+1
∴ y≤1
If P has no original image, then p > 1
And ∵ P belongs to n
The value range of P is {P ∈ n | P ≥ 2}
Is a natural number greater than or equal to 2

If there is a real number θ such that 2x & # 178; - 4xsin θ + 3cos θ = 0, then the value range of X is_____

If there is a real number θ, such that 2x & # 178; - 4xsin θ + 3cos θ = 0 holds, that is, if there is a real number θ, such that 4xsin θ - 3cos θ = 2x & # 178; holds, √ (16x ^ 2 + 9) sin (θ + φ) = 2x & # 178;, sin (θ + φ) = 2x & # 178; / √ (16x ^ 2 + 9), | sin (θ + φ) |

There is a real number x such that ax & # 178; - 2x + 2 ＜ 0 holds, and the value range of a is obtained

When a = 0, there is - 2x + 21
When a is not zero, x = 0 is obviously not the solution, so there is a