Given that the point P (1,4) is on the circle C: x2 + Y2 + 2ax-4y + B = 0, the symmetric point of point P about the straight line x + Y-3 = 0 is also on the circle C, then a=______ ，b=______ ．

Given that the point P (1,4) is on the circle C: x2 + Y2 + 2ax-4y + B = 0, the symmetric point of point P about the straight line x + Y-3 = 0 is also on the circle C, then a=______ ，b=______ ．

Let P (1,4) be a line x + Y-3 = 0 and P ′ (x0, Y0) be a symmetric point. Then the slope k of the line PP ′ = Y0 − 4x0 − 1 = 1. ① the midpoint m (x0 + 12, Y0 + 42) of the line PP ′ is on the line x + Y-3 = 0, and 〈 x0 + 12 + Y0 + 42-3 = 0

Given that 0 is less than a and less than B, and that the line 2aX by + 2 = 0 always bisects the circumference of the square of the circle x + the square of the circle y + 2x-4y + 1 = 0, is the following inequality correct?
A.log2a＞1 B.log2a+log2b≥-2 C.log2（b-a）＜0 D.log2（b/a+a/b）＜1

First of all, the coordinates of the center of the circle are (- 1,2), and it is easy to get a + B = 1