In a metal smelter, 27 square ingots of the same size were melted in the furnace and then fired into a rectangular ingot. The length, width and height of the rectangular ingot were measured to be 160cm, 80cm and 40cm respectively. What was the original edge length of the square ingot?

In a metal smelter, 27 square ingots of the same size were melted in the furnace and then fired into a rectangular ingot. The length, width and height of the rectangular ingot were measured to be 160cm, 80cm and 40cm respectively. What was the original edge length of the square ingot?

According to the meaning of the title: 3160 × 80 × 40 △ 27 = 351200027 = 803 (CM), then the edge length of the original cube ingot is 803cm

27 cubes of the same size were cast into a cuboid ingot. The length, width and height of the cuboid were measured to be 160cm, 80cm and 40cm respectively, and the original value was calculated

Cuboid volume = 16 * 8 * 4 = 512 cubic decimeters
Cube volume = 512 / 27 cubic decimeter
Cube side length = (512 / 27) cube root = 8 / 3M

The length, width and height of a cuboid are three consecutive natural numbers. Its volume is 120 cubic centimeters. What is its surface area?

120=2×2×2×3×5
2×2=4
five
2×3=6
The length, width and height are 6cm, 5cm and 4cm respectively
2 × (6 × 5 + 6 × 4 + 4 × 5) = 148 square centimeters