When Xiao Fang calculates a + bc-a ^ 2 / A ^ 2 + B ^ 2 + C ^ 2 (a, B, C are not equal to each other), he finds that if a and B are exchanged, the value of this formula remains unchanged, If a + B + C = 1, the constant value a + (bc-a ^ 2 / A ^ 2 + B ^ 2 + C ^ 2) bc-a ^ 2 is a molecule

When Xiao Fang calculates a + bc-a ^ 2 / A ^ 2 + B ^ 2 + C ^ 2 (a, B, C are not equal to each other), he finds that if a and B are exchanged, the value of this formula remains unchanged, If a + B + C = 1, the constant value a + (bc-a ^ 2 / A ^ 2 + B ^ 2 + C ^ 2) bc-a ^ 2 is a molecule

Construct an algebraic expression containing the letters P and Q, so that no matter what the values of P and Q are, the value of the algebraic expression is always negative. How many such algebraic expressions can be written? (if finite, list all, if infinite, explain the reason)

-P & # 178; Q & # 178; - 1. Infinite, as long as P and Q are even power, so that the product of even power of (PQ) must be greater than or equal to 0, plus a negative sign before it must be less than or equal to 0, and minus a positive number after it, it must be less than or equal to 0

This paper constructs an algebraic expression containing the letters P and Q, so that no matter what the values of P and Q are, the value of the algebraic expression is always negative. How many such algebraic expressions can be written?

-lpl-lql
-p^2-q^2
-lpl-q^2
-p^2-lql

Decomposition factor (x + 2Y) &# 178; - X & # 178; - 2XY - 7m (m-n) &# 179; + 21mn (n-m) &# 178; (3a-4b) (7a-8b) + (11a + 2b) (8b-7a)

Thank you

2m-3

M is less than - 9

2m-3=7m-3/2
solve equations:
2m-3=7m-3/2

  2m-3=7m-3/2
2m-7m=-3/2+3
-5m=3/2
m=-3/10

9a-5+4a;
(2) Simplification: 9a-5 + 4a; 3Y * 6 + 4Y
(3) Simplification: the square of 8x - 5x * 2

9a-5+4a
=13a-5
3y*6+4y
=18y+4y
=22y
The square of 8x - 5x * 2
=8x^2-10x
=2x(4x-5)

First simplify and then evaluate: 3 (M + 1) ^ 2 + 4 (M + 1) (m-1) - 7m (m-1), where M = 2
The main is to simplify the process, must be detailed, as for what can be substituted into the evaluation without

3(m+1)^2+4(m+1)(m-1)-7m(m-1)
=3(m^2+2m+1)+4(m^2-1)-7m^2+7m
=3m^2+6m+3+4m^2-4-7m^2+7m
=13m-1
When m = 2
simple form
=13*2-1
=25

It is known that a, B and C are real numbers of incomplete equality, and it is proved that: (B + C-A) / A + (c + a-b) / B + (a + B-C) / C > 3
Come on, I'm going crazy

Given that A.B.C is a real number and √ A & # 178; - 2a-3 ＋| B + 1 | + (c + 2) &# 178; = 0, find the roots of the equation a χ & # 178; + B χ + C = 0
(A-3) in the radical

√a²－2a－3 ＋| b＋1 |＋﹙c＋2﹚²＝0
So a & # 178; - 2a-3 = 0, B + 1 = 0, C + 2 = 0
So a = - 1 or 3 B = - 1 C = - 2
When a = - 1, a χ & # 178; + B χ + C = 0, that is - X & # 178; - X-2 = 0, the discriminant less than 0 has no solution
When a = 3, a χ & # 178; + B χ + C = 0, that is, 3x & # 178; - X-2 = 0, the solution is x = 1 or x = - 2 / 3
I'm very glad to answer your questions. Outsiderl will answer your questions
If there is anything you don't understand, you can ask. The top right corner of the mobile client is satisfied