What are the solutions of the equations (1) 7x + 3y-5z = 8 (2) y: X: z = 5:3:8?

What are the solutions of the equations (1) 7x + 3y-5z = 8 (2) y: X: z = 5:3:8?

We can set Y: X: z = 5:3:8
X=3K,Y=5K,Z=8K
Substituting (1)
21K+15K-40K=8
-4K=8
K=-2
therefore
X=-6
Y=-10
Z=-16

Solutions of the system of equations 2x-3y = 6 3x + 4Y = 6

2X-3Y=6………… ①
3X+4Y=6………… ②
② X 2 - 1 × 3
17y=-6
y=-6/17
① 4 + 2 × 3
17x=42
x=42/17
∴x=42/17,y=-6/17

Given that the tangent equation of the image of function y = f (x) at point (1, f (1)) is y = 3x-2, then the tangent equation of the image of function g (x) = x2 + F (x) at point (1, G (1)) & nbsp; is y = 3x-2______ ．

From the tangent equation of the image of the function y = f (x) at the point (1, f (1)) is y = 3x-2, we get that f '(1) = 3, f (1) = 1. And the function g (x) = x2 + F (x), then G' (1) = 2 × 1 + F '(1) = 2 + 3 = 5. G (1) = 12 + F (1) = 1 + 1 = 2. The tangent equation of the image of the function g (x) = x2 + F (x) at the point (1, G (1)) is Y-2 = 5 (x-1) That is, 5x-y-3 = 0