The overlapped part of a graph accounts for 18% of the area of the large circle and 15% of the area of the small circle. (1) if the area of the large circle is known to be 25 square decimeters, calculate the area of the small circle. (2) if the area of the overlapped part is 25 square centimeters, then what is the total area of the graph?

The overlapped part of a graph accounts for 18% of the area of the large circle and 15% of the area of the small circle. (1) if the area of the large circle is known to be 25 square decimeters, calculate the area of the small circle. (2) if the area of the overlapped part is 25 square centimeters, then what is the total area of the graph?

(1) 25 × 18 / 15 = 120 / 15 = 14 (square decimeter) a: the area of the small circle is 14 square decimeter. (2) 25 / 18 + 25 / 15-25 = 165 + 105-25 = 245 (square centimeter) a: the total area of the figure is 245 square centimeter

The overlapping part in the figure accounts for 1 / 8 of the area of the big circle and 1 / 5 of the area of the small circle. It is known that the area of the big circle is 2 / 5 square decimeters. How to calculate the area of the small circle?

2 / 5 × 1 / 8 △ 1 / 5 = 1 / 4 square decimeter

As shown in the figure, a is the common part of two circles. The area of a is 1 / 8 of the big circle and 5 / 12 of the small circle. Find the ratio of the area of the small circle to the area of the big circle

The ratio of small circle area to large circle area is 1 / 8:5 / 12 = 3:10