As shown in the figure, in the triangle ABC, the angle ABC = 45 degrees, and H is the intersection point of the higher he be

As shown in the figure, in the triangle ABC, the angle ABC = 45 degrees, and H is the intersection point of the higher he be

Let ad be the height of BC and d be the perpendicular foot. It is easy to know that for △ EAH ∽ DAC, ≌ C = ≌ ahe = ≌ Bhd and ≌ BDH = ≌ ADC = 90 ° because ≌ ABC = 45 degrees, ≌ BDA is an isosceles right triangle, that is, ≌ BD = ad, so ≌ BDH ≌ ADC, so BH = AC

As shown in the figure, in RT △ AB, if the length of high AE and middle line ad on hypotenuse BC are 5 and 6 respectively, what is the area of RT △ ABC?

In RT △ AB, it is easy to get ad = BD = DC = 6 from the middle line
Then BC = 12 is the bottom edge
The height is AE = 5
The area is 30

In △ ABC, ad ⊥ BC is greater than D, and ADBC = 13, then the maximum value of acab + ABAC is______ ．

Let ad = a, then BC = 3aacab + ABAC = AB2 + ac2ab · AC = BC2 + 2Ab · AC · cos ∠ bacab · AC = 9a2ab · AC + 2cos ∠ BAC. ∵ s △ ABC = 12ad · BC = 12ab · acsin ∠ BAC ∵ 9a2ab · AC = 3sin ∠ BAC ∵ acab + ABAC = 3sin ∠ BAC + 2cos ∠ BAC = 13sin (∠ BAC + α) ≤ 13

The school allocated 560 trees to three classes, 47 students in one class, 45 students in two classes, 48 students in three classes. How many trees should be planted in each class

Agree

The school purchased 560 sets of desks and chairs and distributed them to each class according to the number of three classes in Grade 6. There are 47 students in class 1, 45 students in class 2 and 48 students in class 3 in Grade 6
How many sets will each of the three classes move?

There are 140 students in three classes, 560 sets of tables, 4 sets for each
The first class is 47 * 4 = 188 sets, the second class is 45 * 4 = 180 sets, the third class is 48 * 4 = 192 sets~

The school plans to divide the task of planting trees to grade 6 and other grades according to 5:3. Results the number of trees planted in Grade 6 accounts for 75% of the whole school, 20 more than the plan. How many trees did the school plan to plant?

5 + 3 = 8.20 (75% - 58), = 20 (34 − 58), = 20 (18), = 160 (trees)

The area of a triangle vegetable field is 196 square meters, the length of the bottom is 24.5 meters, how many meters is the height

Reprint of Chinese,
196 × 2 △ 24.5 = 16 (m)

There is a triangular vegetable field, with an area of 24 1 / 4 square meters, a height of 3 13 / 28 meters and a bottom length of several meters

24 and 1 / 4 × 2 △ 3 and 13 / 28
=97/2÷97/28
=14m

A triangle vegetable field, 16 meters high, 352 square meters in area. How much is the bottom of this vegetable field
By the way, 10 - (6.75-3.5) divided by 13 is a simple operation

The bottom edge is 352x2 △ 16 = 44m

The area of a triangle is 125 square decimeters less than that of a parallelogram with the same base and height. How many square decimeters is the area of a parallelogram row

S parallelogram = base * height
S triangle = 1 / 2 bottom * height
Equal base and equal height
S parallelogram = 2 * 125 = 250dm ^ 2