As shown in the figure, in the equilateral triangle ABC, D and E are the points on the sides of AB and BC respectively, ad = be, AE intersects CD at point F, Ag ⊥ CD at point G, if Ag = 2, then the value of AF is () A. 52B. 32C. 34D. 433

As shown in the figure, in the equilateral triangle ABC, D and E are the points on the sides of AB and BC respectively, ad = be, AE intersects CD at point F, Ag ⊥ CD at point G, if Ag = 2, then the value of AF is () A. 52B. 32C. 34D. 433

In △ ace and △ CBD, AC = CB ∠ ace ＝ CBD = 60 ° CE = BD ≠ ace ≌ CBD, ≠ CAE = BCD, AFG = CAF + ACF = BCD + ACF = 60 ° in △ ace and △ CBD, sin ∠ AFG = agaf, i.e. sin60 ° = 2AF, the solution is AF = 433

In the equilateral triangle ABC, D and E are the points on the sides of AB and BC respectively, and BD = CE, AE intersects with CD at F, Ag is perpendicular to CD at g, 1

1. In △ BDC and △ CEA
BD=CE;∠B=∠ECA；BC=CA
So △ BDC ≌ △ CEA
Therefore, BCD = fac
Because ∠ AFG = ∠ fac + ∠ FCA = ∠ BCD + ∠ FCA = 60 degree
2. Because ∠ AFG = 60 °, FG / AF = 1 / 2

In isosceles △ ABC, the median line BD on one waist AC divides the circumference of △ ABC into two parts, 12cm and 15cm, and calculates the length of each side of △ ABC

As shown in the figure, ∵ BD is the middle line, ∵ 12cm is the sum of waist length and half of waist length, waist length = 12 △ 1.5 = 8cm, bottom edge = 15-8 × 12 = 11cm, three sides of triangle are 8cm, 8cm and 11cm respectively, which can form triangle, 15cm is the sum of waist length and half of waist length, waist length = 15 △ 1.5 = 10cm, bottom edge = 12-10 × 12 = 7cm, three sides of triangle are 10cm, 10cm and 7cm respectively, which can form triangle The length of each side of △ ABC is 8cm, 8cm, 11cm or 10cm, 10cm, 7cm respectively

In the triangle ABC, ab = AC, BD is the center line on the side of AC. BD divides the circumference of ABC into two parts, 36 and 63, and calculates the length of BC

AB + ad = 36 (63) ~ 1BC + CD = 63 (36) ` 2ad = cdab = AC1 + 2 = AB + AC + BC = 2Ab + BC = 99 '` 32-1 = bc-ab = 47 (- 27) ` 4. Then, from the third and fourth formulas, we get BC = 64.33333333 (rounding off, because the sum of the two sides of the triangle is greater than the third side) BC = 15

As shown in the figure, after cutting the largest straight triangle from a right angled trapezoid, the remaining area is 120 square centimeters. If you cut the largest parallelogram from this figure, how many square centimeters is the area of the parallelogram?

120 × 2 △ 15 = height of 16 cm trapezoid
15 × 16 = 240 square centimeter area of parallelogram
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It's a trapezoid. The top bottom is 15cm. The bottom is 28cm. The height is 16cm. Cut the biggest triangle. What's the figure left? What's the area of the figure left?
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Cut the largest triangle, the bottom of the triangle is the largest = the bottom, the maximum height of the triangle is the trapezoidal height
The rest is still a triangle, bottom = upper bottom, height = trapezoidal height
The remaining area = 15 × 16 △ 2 = 120 square centimeter
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The upper bottom of a trapezoid is 12 decimeters, the lower bottom is 10 decimeters, and the height is 8 decimeters. How many square decimeters is its area?

S=8(12+10)/2=88

Cut the largest triangle from the trapezoid on the right. What is the shape of the remaining figure? Find the remaining area?
The upper sole is 15cm, the lower sole is 35cm and the height is 10cm

Triangle
Triangle area = (10x15) / 2 = 75cm 2

For a trapezoid, the upper bottom is increased by 25 meters to form a parallelogram, the area is increased by 125 square meters, and the upper bottom is reduced by 65 meters to form a triangle. How many square meters is the original trapezoid area?
If the upper and bottom of a trapezoid increase by 25 meters, it will become a parallelogram, and the area will increase by 125 square meters. If the upper and bottom decrease by 65 meters, it will become a triangle?

125 * 2 / 25 = 10m, height
65 + 25 = 90m, bottom
65 M. top and bottom
Area (90 + 65) * 10 / 2 = 775 square meters

Parallelogram is 1.2 meters high, triangle area is 2 times of parallelogram, how many decimeters is the height of this triangle

4.8 decimeters. 1.2 × 2 × 2 because a triangle with equal base and height is twice as big as a parallelogram