It is known that the median line on the waist of an isosceles triangle is divided into two parts with circumference of 20 and 36. Find the length of the bottom and waist of the triangle I remember again, Set: waist a, bottom B 0.5a+b=20 a+0.5a=36 、/ A = 24 b=8 2; 0.5a+a=20 0.5A + B = 36 does not hold

It is known that the median line on the waist of an isosceles triangle is divided into two parts with circumference of 20 and 36. Find the length of the bottom and waist of the triangle I remember again, Set: waist a, bottom B 0.5a+b=20 a+0.5a=36 、/ A = 24 b=8 2; 0.5a+a=20 0.5A + B = 36 does not hold

Method 1: let waist a, bottom B (1) 1 / 2A + B = 20A + 1 / 2A = 36, the solution is a = 24, B = 8 (2) 1 / 2A + a = 201 / 2A + B = 36, the solution is a = 40 / 3, B = 88 / 32A 〈 B, the solution is not tenable if it does not satisfy the condition that any two sides of triangle and greater than the third side

The circumference of an isosceles triangle is 16, one side is 6, and the other two sides are 6______ ．

When the waist is 6, the other two sides are 4,6, and 4 + 6 ＞ 6, which satisfies the trilateral relation theorem; when the bottom is 6, the other two sides are 5,5,5 + 5 ＞ 6, which satisfies the trilateral relation theorem, so the other two sides of the isosceles triangle are: 6,4 or 5,5. So the answer is: 6,4 or 5,5

If the circumference of an isosceles triangle is 16 and the height of its base is 4, then the length of its base is 4______ ．

Let the waist length be x and the bottom edge length be 2Y, then 2x + 2Y = 16, 42 + y2 = x2. From this we can get y = 3, so the bottom edge length is 6