It is known that the area of triangle AOB is 15 square centimeters, and the length of line ob is 3 times of OD. The area of trapezoid ABCD is calculated

It is known that the area of triangle AOB is 15 square centimeters, and the length of line ob is 3 times of OD. The area of trapezoid ABCD is calculated

According to the question stem, we can get: BD = 43BO, △ abd area: 43 × 15 = 20 (square centimeter), ad: BC = od: OB = 1:3, because the height of △ abd and △ BDC is the same, so the area ratio of △ abd and △ BDC is 1:3, then the area of △ BDC is: 20 × 3 = 60 (square centimeter), 20 + 60 = 80 (square centimeter), a: the area of this trapezoid is 80 square centimeter

It is known that the area of triangle AOB is 15 square centimeters, and the length of line ob is 3 times of OD. The area of trapezoid ABCD is calculated

According to the question stem, we can get: BD = 43BO, △ abd area: 43 × 15 = 20 (square centimeter), ad: BC = od: OB = 1:3, because the height of △ abd and △ BDC is the same, so the area ratio of △ abd and △ BDC is 1:3, then the area of △ BDC is: 20 × 3 = 60 (square centimeter), 20 + 60 = 80 (square centimeter), a: the area of this trapezoid is 80 square centimeter

Trapezoid ABCD, diagonal AC, BD, intersection point O, line Bo is 3 times OD, triangle ABO area is 9 square centimeters, find trapezoid ABCD area?

The first point is that the area ratio of similar triangles is equal to the square of the corresponding side length ratio. The second point is that the area ratio of two triangles with the same height and different bottom is equal to the ratio of the bottom of the two triangles. The details are as follows: because Bo: OD = 3:1, the area product of triangle AOB: the area of triangle doc = 9:1, because