If you extend the top and bottom of a right angle trapezoid by 5cm, the area will increase by 15cm, and it will become a square. What is the area of the original trapezoid

Side length of square: 15 × 2 △ 5 = 6 cm
Square area: 6 × 6 = 36 cm & # 178;
Area of trapezoid: 36-15 = 21 cm & # 178;

A right angled trapezoid has an upper base of 6cm. If the lower base is shortened by 2cm, it will become a square. How many square centimeters is the original trapezoid area?

If the bottom of a right angled trapezoid is shortened by 12 cm, it will become a square, and the area is reduced by 36 square cm. Find the area of the right angled trapezoid
A trapezoid has an upper bottom of 5 cm and a lower bottom of 10 cm. If the upper bottom is extended by 3 cm, the area will increase by 36 square cm. What is the area of this trapezoid

1. Gao Wei
36 × 2 △ 12 = 6 (CM)
The area of right angled trapezoid is
6 × 6 + 36 = 72 (cm2)
2. Gao Wei
36 × 2 △ 3 = 24 (CM)
The area of the trapezoid is
(5 + 10) × 24 △ 2 = 180 (square centimeter)

It is known that the length of the top and bottom of an isosceles trapezoid is 2cm and 6cm respectively, and its two diagonals are perpendicular to each other. What is the area of this trapezoid?

The trapezoid ABCD translation diagonal AC (or BD) intersects the extension line of BC at E
So aced is a parallelogram because BD is perpendicular to AC and AC is parallel to de
So BDE = 90 degrees
So the triangle BDE is an isosceles right triangle
So the square of BD + the square of de = the square of be
So BD = de = 4 times root 2
Let DF be perpendicular to be, so DF is the center line of be side
DF=4
So the area of trapezoid ABCD = (2 + 6) times 4 times half = 16 square centimeters

For a right angle trapezoid, the ratio of the upper and lower bottom is 2:3. Increase the upper bottom by 6cm and the lower bottom by 2cm to form a square. What is the area of the trapezoid?

Hello
The original upper and bottom (6-2) / (3-2) x2 = 8cm
Bottom 8x3 / 2 = 12cm
Height 8 + 6 = 14cm
Trapezoid area (12 + 8) x14 △ 2 = 140 square centimeter
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Given that the top and bottom of an isosceles trapezoid are 2cm and 6cm respectively, and its two diagonals are perpendicular to each other, what is the area of the trapezoid? (calculation process)

If the length of the two bottom of the trapezoid is 2cm and 8cm respectively, and the two diagonal lines are 6cm and 8cm respectively, the area of the trapezoid is?

Make a parallel line of 8 cm long diagonal line, intersect with another diagonal line at an end point, and form a triangle. The triangle has three sides, and the length is 6, 8, and 10 cm (8 + 2 = 10 cm), so the triangle is a right triangle. And the part of the triangle that does not coincide with the trapezoid and the part that does not coincide with the trapezoid is equal

The area of a trapezoid is 18 square centimeters, the upper bottom is 4 centimeters, and the height is 3 centimeters. Its lower bottom is () centimeters

Bottom = 18 × 2 △ 3-4 = 8 cm

The area of a trapezoid is 16 square centimeter, the upper bottom is 4 centimeter, the lower bottom is 6 centimeter, and the height is () centimeter

Trapezoid area = 1 / 2 × (upper bottom + lower bottom) × height
So the height = 16 × 2 ^ (4 + 6) = 3.2 cm
A: the height is 3.2 cm

It is an isosceles trapezoid, the upper bottom is 0.7m, the lower bottom is 1m, and the height is 4m,

S ladder = (upper bottom + lower bottom) times height divided by 2
S ladder = (0.7 + 1) times 4 divided by 2
=3.4m
And because the middle height = (upper bottom + lower bottom) divided by 2
So the middle height = s divided by the height
=3.4 divided by 4
=1.7 divided by 2
=0.85m

If you extend the top and bottom of a right angle trapezoid by 5cm, the area will increase by 15cm, and it will become a square. What is the area of the original trapezoid