Factoring in real numbers: x ^ 2-3x-1 It's better to have steps, what method to use, and talk about ha and 3Q

Factoring in real numbers: x ^ 2-3x-1 It's better to have steps, what method to use, and talk about ha and 3Q


x^2-3x-1
=(x-3/2)^2-9/4-1
=(x-3/2)^2-13/4
=(x-3/2+√13/2)(x-3/2-√13/2)
=(x-(3-√13)/2 )(x-(3+√13)/2)



Factoring in real numbers: 3x ^ 2 + X-1


Original formula = 3 (X & # 178; + X / 3-1 / 3)
=3(x²+x/3+1/36-1/36-1/3)
=3[(x+1/6)²-13/36]
=3(x+1/6+√13/6)(x+1/6-√13/6)



Decompose the following factor 3x-5 in the range of real numbers


There is no solution to this problem