Explain Qin Jiushao's algorithm to me. I don't know much about it,

Explain Qin Jiushao's algorithm to me. I don't know much about it,

This paper rewrites an n-degree polynomial f (x) = a [n] x ^ n + a [n-1] x ^ (n-1) +. + a [1] x + a [0] into the following form: F (x) = a [n] x ^ n + a [n-1] x ^ (n-1)) +. + a [1] x + a [0] = (a [n] x ^ (n-1) + a [n-1] x ^ (n-2) +. + a [1]) x + a [0] = ((a [n] x ^ (n-2) + a [n-1] x ^ (n-3) +. + a [2]) x + a [1]) x + a [0] = ((a [n] x ^ (n-2) + a [1])

Using Qin Jiushao algorithm to calculate
F (x) = 12-8x ^ 2 + 6x ^ 4 + 5x ^ 5 + 3x ^ 6

f(x)=12-8x^2+6x^4+5x^5+3x^6
=3x^6+5x^5+6x^4-8x^2+12
=(((3x+5)x+6)x^2-8)x^2+12
V4=((3x+5)x+6)x^2-8
If x = 4, we can get the following result
v4=1176

If x3-6x2 + 11x-6 = (x-1) (x2 + MX + n), find: (1) the value of M and N; (2) the square root of M + n; (3) the cube root of 2m + 3N

(1) ∫ (x-1) (x2 + MX + n) = X3 + (m-1) x2 + (n-m) x-n = x3-6x2 + 11x-6 ∫ M-1 = - 6, - n = - 6, the solution is m = - 5, n = 6; (2) when m = - 5, n = 6, the square root of M + n = - 5 + 6 = 1, 1 is ± 1; (3) when m = - 5, n = 6, the square root of 2m + 3N = - 10 + 18 = 8, 8 is 2