Four character idioms with numbers `````

Four character idioms with numbers `````


One in a hundred, one in a hundred
No two loyalty, no two saying, no two nothing, no two sure two Ding Yimao two Ding yique two unique merit, one beauty, two noble and one humble, no two golden hairpin twelve monarch's life, no two in succession, a little knowledge of one or two, three occupation, no two loyalty, no two vowing to death, no two number one, no two saying, no two first, no two hearing, no two general, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two, no two There's no two, there's no two and there's no two
Company two, company two, company three, company two, company three, company three, company three, company three
No, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no, no
To be concerned about something, to cheat something, to pull something, to pull something, to pull something
Three to five, three to five, ten to five, ten to ten, five to five, five to three, five to five, five to five, five elements, three to five, two to one, five to five, two to one, five to three
Four not hard six hate five scold six shout six shout six parallel four Li six four not hard six
It's all over the place. It's all over the place. It's all over the place
Nine out of ten



Simple operation: the third power of one-half square multiplied by the fifth power of 2


The third power of one-half square x the fifth power of two
=1 ^ 6 / 2 × 2 ^ 15
=1 ^ 6 × 2 ^ 6 × 2 ^ 9
=(1 / 2 × 2) ^ 6 × 2 ^ 9
=2^9
=512



-The third power of B is multiplied by the second power of B


Equal to the fifth power of - B



The result of the sixth power of a multiplied by the third power of (the second power of a multiplied by B)


a^6×(a^2b)^3=a^6×a^6b³=a^12b³



If the sequence an = (1 + 1 / N) ^ n, prove an


a_ (n + 1) = (1 + 1 / (n + 1)) ^ (n + 1) = (1 / N + 1 / N +... + 1 / N + 1 / (n + 1)) ^ (n + 1) > [(n + 1) (1 / ((n ^ n * (n + 1))) open (n + 1) power root] ^ (n + 1) (mean inequality) = (n + 1) ^ (n + 1) * 1 / ((n ^ n) * (n + 1)) = (n + 1) ^ n / N ^ n = ((n + 1) / N) = (n + 1) ^ n



The sequence {an} satisfies A1 = 1, an = a (n-1) + (3) n-1 power (n > = 2). One: find a2a3. Two: prove an = (3) n-1 power divided by 2


A1 = 1, an = a (n-1) + (3) n-1 power (n > = 2), n = 2A2 = a1 + 3 = 1 + 3 = 4N = 3a3 = A2 + 9 = 4 + 9 = 13a2a3 = 4 * 13 = 52an = a (n-1) + (3) n-1 power: an = 3 ^ (n-1) + a (n-1) -- > an-a (n-1) = 3 ^ (n-1) the same a (n-1) - A (n-2) = 3 ^ (n-2) a(n-2(-a(n-3)=3^(n-3) ………… ...



Given the sequence {an}, where an = 2 to the nth power + 3 to the nth power, and the sequence {a (n + 1) - Pan} is an equal ratio sequence, then the constant P is?


p=2 or p=3



If the sum of the first n terms of the sequence {an} is the nth power of Sn = A-1 (a ≠ 0), then what is the characteristic of the sequence?


When n = 1, A1 = S1 = A-1; when n > 1, Sn = a ^ n-1, s (n-1) = a ^ (n-1) - 1, then an = SN-S (n-1) = (a ^ n-1) - [a ^ (n-1) - 1] = a ^ n-a ^ (n-1) = a ^ (n-1) * A-A ^ (n-1) = (A-1) * a ^ (n-1) = A1 * a ^ (n-1). When A1 = A-1 = 0, i.e. a = 1, all terms of the sequence are 0; when A1 = A-1 ≠ 0, i.e. a ≠



Find the first n terms and Sn of sequence {n / 3 to the nth power}


Sn = 1 / 3 + 2 / 3 ^ 2 + 3 / 3 ^ 3 +... + n / 3 ^ n ① Sn / 3 = 1 / 3 ^ 2 + 2 / 3 ^ 3 + 3 / 3 ^ 4 +... + n / 3 ^ (n + 1) ② - ② 2Sn / 3 = 1 / 3 + 1 / 3 ^ 2 + 1 / 3 ^ 3 +... + 1 / 3 ^ N-N / 3 ^ (n + 1) = (1 / 3) (1-1 / 3 ^ n) / (1-1 / 3) - N / 3 ^ (n + 1) = (1-1 / 3 ^ n) / 2-N / 3 ^ (n + 1) so Sn = 3 (1-1 / 3 ^ n) - N / 2 * 3 ^ n



The law of sequence 21, 31, 47, 56, 69, 72
8 didn't show up,


Law: ten digits into arithmetic sequence
One digit number zero never appears