Given 3x + 2Y = 0, find the value of [1 + (2 * y ^ 2) / (x ^ 2-y ^ 2)] [1 - (2Y) / (x + y)]

Given 3x + 2Y = 0, find the value of [1 + (2 * y ^ 2) / (x ^ 2-y ^ 2)] [1 - (2Y) / (x + y)]

Y / x = - 3 / 2 is obtained from 3x + 2Y = 0, and Y / x = M. in the first bracket, the numerator and denominator are divided by x ^ 2; in the second bracket, the numerator and denominator are divided by X to get [1 + (2 * y ^ 2) / (x ^ 2-y ^ 2)] [1 - (2Y) / (x + y)] = [1 + 2m ^ 2 / (1-m ^ 2)] [1 + 2 * (- 3 / 2) ^ 2 / (1 - (...)

3x-2y=1 x-y=2

From X-Y = 2 we get x = y + 2
If we take 3x-2y = 1, we get 3 (y + 2) - 2Y = 1
y=-5
x=y+2=-3

2x-5y + 13 = 0 and 9x + 6y-8 = 0

x =-38/57
y=7/3

1. In a right triangle, if the difference between two acute angles is 26 degrees, the smaller acute angle is? 2. Solve the equations: 2x-5y = - 13,9x + 6y = 8

cuole
It's 32 degrees
Let the smaller acute angle be x degree
x+x+26=90
x=32
Multiply the second equation by 9, subtract the second equation by 2, and then solve it by yourself

Given the system of quadratic equations 9x-5y = 8 7x-6y = 7, then the value of the algebraic formula 6-2x-y is

7x-6y-(9x-5y)=7-8
7x-6y-9x+5y=-1
-2x-y=-1
6-2x-y=-1+6
62x-y=5

If the equation 4x + K (1 − x) 1 + x = 3 of X has negative roots, then the value range of K is ()
A. K is not equal to 2B. K > 3 or K < 1C. - 3 < K < 1D. 1 < K < 3 and K is not equal to 2

If the root of the equation is negative, it must be 3 − K1 − K ＜ 8, 3 − K ＞ 81 − K ＜ 8 or 3 − K ＜ 81 − K ＞ 8, and X ≠ - 1, that is, 3-K ≠ - 1 + K. the solution is 1 ＜ K ＜ 3 and K is not equal to m, so choose D

The polynomial 6x2 + mxy-3y2 + 3x + 10y-3 can be decomposed into two polynomials of degree x, y=

6x2+mxy-3y2+3x+10y-3
Let's decompose it into
(ax+by+3)(nx+py-1)
After expansion, the corresponding original formula can be obtained
an=6
ap+nb=m
3n-a=3
3p-b=10
pb=-3
The solution is m = 7
The others are a = 3, B = 1, n = 2, P = 3, B = - 1,

The polynomial 6x ^ 2 + 7xy-3y ^ 2-8x + 10Y + M can be decomposed into the product of two first-order factors to find the value of M

The polynomial can be decomposed into (2x + A + 3Y) (3x + B-Y)
Multiplication yields 6x ^ 2 + 7xy-3y ^ 2 + (2B + 3a) x + (3b-a) y + ab
The equation is as follows
2b+3a=-8
3b-a=10
m=ab
The solution is available
a=-4
b=2
Then M = - 8

Factorization of 2x2 + xy-3y2 + X + 4y-1

2x²＋xy-3y²＋x＋4y-1
=2× x × x ＋x ×y-3×y×y＋x＋4×y-1
=x ×2x＋x×y-y×3y＋x ×1＋y×4-1
=x ×（2x＋y＋1）-y×（3y＋4）-1

7x-8 + (- 3x + 20) = 8 7x + 8 = 3x + 12 half - 6 = Four Thirds 9-3y = 5Y + 5 3x-7 (x-1) = 3-2 (x + 3) 2 * 1200X = 2000 (22-x)
Writing process

7x-8 + (- 3x + 20) = 8 7x-8-3x + 20 = 8 4x = - 4 x = - 1 7x + 8 = 3x + 12 4x = 4 x = 1 half - 6 = Four Thirds wrong 9-3y = 5Y + 5 8y = 4 y = 1 / 2 3x-7 (x-1) = 3-2 3x-7x + 7 = 1 4x = 6 x = 3 / 2 (x + 3) 2 * 1200X = 2000 (22-x) 2400x ^ 2 + 3600x + 2000x-44000 = 0 2400x ^ 2 + 5600-44000 = 0 x = (- 7 ± root 709) / 6