As shown in the figure, it is known that ray OC divides angle AOB into 1:3 parts and ray od divides angle AOB into 5:7 parts. If angle cod = 15 degrees, try to judge the position relationship between OA and ob

As shown in the figure, it is known that ray OC divides angle AOB into 1:3 parts and ray od divides angle AOB into 5:7 parts. If angle cod = 15 degrees, try to judge the position relationship between OA and ob

Let AOC degree of angle be x and BOD degree of angle be y
If the angle AOB is divided into two parts by OC, then x: (15 + y) = 1:3
Od divides AOB into 5:7, then (x + 15): y = 5:7
The solution is x = 22.5 ° y = 52.5 °
Then angle AOB degree = 22.5 + 15 + 52.5 = 90 degrees
OA is perpendicular to ob

In the triangular pyramid o-abc, ∠ AOB = ∠ COA = 60 ° and ∠ BOC = 90 °,
Find the degree of the dihedral angle with OA as the edge

When drawing, make OBC as the bottom and mark the angle. You will find that OAB is an isosceles right triangle. Make a vertical line BH from B to OA and connect ch to get ch perpendicular to OA. Set the length of OB edge as 1, calculate the length of Hb, HC and BC, and calculate the angle BHC

In the acute triangle ABC, a = 50 degrees, the vertical bisectors of AC and BC intersect at point O, and the degree of BOC is calculated
Please

100°