The area of the triangle formed by the line y = KX + 3 and the two coordinate axes is 9, and the value of K is obtained

The area of the triangle formed by the line y = KX + 3 and the two coordinate axes is 9, and the value of K is obtained

When x = 0, y = 3, when y = 0, x = - 3 / K. The triangle area is x * y / 2 = (- 3 / k * 3) / 2 = - 18 / k = 9, so k = - 2

Given that the area of the triangle formed by the line y = KX + B passing through the point (5 / 2,0) and the coordinate axis is 25 / 4, the analytical formula of the line is obtained
Y = - 2x + 5 and y = 2x-5

Taking the intersection of image and Y-axis and Y-point as an example, the formula of area is: 1 / 2 × I oy I × I Ox I = 25 / 41 / 2 × I oy I × 5 / 2 = 25 / 4, the solution is y = ± 5, substituting (5 / 2,0), (0,5) and (5 / 2,0), (0, - 5) into the analytic formula y = KX + b 0 = 5 / 2K + B = 5; 0 = 5 / 2K + B = - 5, respectively

It is known that the area of the triangle formed by the line y = KX + 10 and two coordinate axes is 5
Given that the area of the triangle formed by the line y = KX + 10 and the two coordinate axes is 5, the expression of the line is obtained

The intersection of the line and the y-axis is (0,10), so the height of the triangle is 10, then the bottom of the triangle is 1, so the analytical formula of the line is:
Y = x + 10 or y = 10-x