If the line L and the line x + Y-1 = 0 are symmetric about the Y axis, then the equation of the line L is______ ．

If the line L and the line x + Y-1 = 0 are symmetric about the Y axis, then the equation of the line L is______ ．

∵ the slope of the line x + Y-1 = 0 is - 1, and it intersects at (0,1) point on the Y axis, and ∵ the line L and the line x + Y-1 = 0 are symmetrical about the Y axis ∵ the slope of the line L is 1, and it passes through (0,1), then the equation of the line L is y = x + 1, that is, X-Y + 1 = 0, so the answer is: X-Y + 1 = 0

On the solution of the linear equation perpendicular to the known line
The equation of a line passing through (- 3,1) and perpendicular to the line x + 2y-3 = 0 is 2x-y + 7 = 0
What I want to ask is how did 2x-y + 7 = 0 come from
And whether it can be used to solve the equation of a straight line perpendicular to a given point and a straight line in the future

There are many ways, one of which is to
If two lines are vertical, then
k1 * k2 = -1
K1 and K2 are the slopes of the two straight lines respectively
k1 = -0.5
So K2 = 2
So the linear equation is
y = 2x + b,
Bring in (- 3,1) to get the solution

The section ratio of a straight line on x-axis and y-axis is 3 / 2, - 3 respectively,

Let y = ax + B
Because the intercepts on the x-axis and the y-axis are 3 / 2, - 3, respectively
Take (3 / 2,0) and (0, - 3) into the equation respectively
A = 2, B = - 3 can be obtained by solving the equation
So the linear equation is y = 2x-3