Let f (x) be an even function with period 2 and monotonically decreasing on [0,1], then f (- 1 / 2), f (1), f (2) are ()

Let f (x) be an even function with period 2 and monotonically decreasing on [0,1], then f (- 1 / 2), f (1), f (2) are ()

The solution is even function from F (x)
So f (- 1 / 2) = f (1 / 2)
Even functions with F (x) period 2
So f (2) = f (2-2) = f (0)
Then f (x) decreases monotonically on [0,1]
That is, f (0) > F (1 / 2) > F (1)
That is, f (2) > F (- 1 / 2) > F (1)

Given that the function y = f (x) is even, y = f (X-2) monotonically decreases on [0,2], then: a f (0)

0

In the expansion of binomial (3x − 1x) 8, the coefficient of the first term of X is______ ．

In the expansion of (3x − 1x) 8, the general term is tr + 1 = CR8 × (− 1) r × x16 − 5r6, so that the coefficient of the first term of 16 − 5r6 = 1, ∧ r = 2, ∧ x is 28, so the answer is 28