A ^ 2-5ab + 4B ^ 2 = 0, factorization

A ^ 2-5ab + 4B ^ 2 = 0, factorization

A ^ 2 + 5ab + 4B ^ 2 = (a ^ 2 + 2Ab + B ^ 2) + (3AB + 3B ^ 2) = (a + b) ^ 2 + 3B (a + b) = (a + b) (a + 4b) or the result can be obtained directly by cross method, and B is regarded as a constant,

How to decompose a ^ 2 + 10ab + 24B ^ 2? Is the factorization of 998 ^ 2-4 (root 998 + 2) (root 998-2) or 2 (499 / 2-2)?

a²+10ab+24b²=(a+4b)(a+6b）
998²-4=(998+2)(998-2)

Factorization of (a + b) (a + b) + 2 (a + b) + 1

Let u = a + B, then
simple form
=u^2 +2u +1
=(u+1)^2
=(a+b+1)^2