If x2 + y2 = 10, xy = 3, then (X-Y) 2 = ()

If x2 + y2 = 10, xy = 3, then (X-Y) 2 = ()


(x-y)2=x2+y2-2xy=10-2×3=4



If x2 + y2 = 3, X-Y = 2, find the value of XY and the value of X + y, (X2 is the square of x)


X2 + y2 = 3, that is, (X-Y) 2 + 2XY = 3, because X-Y = 2, so (X-Y) 2 = 4,4 + 2XY = 3, xy = 1 / 2, that is, (x + y) 2-2xy = 3, because xy = 1 / 2, so (x + y) 2 = 4, x + y = 2



X2 + y2 = 3, xy = 1, find X-Y


Xy = 1,2xy = 2 (X-Y) ^ 2 = x ^ 2-2xy + y ^ 2 = x ^ 2 + y ^ 2-2xy = 3-2 = 1, so X-Y = 1