What does this sentence mean? Sector CANNOT have bigger area than circle

What does this sentence mean? Sector CANNOT have bigger area than circle

The area of a sector should not be larger than that of a circle

The trajectory equation of the point with the same distance to the line X-Y = 0 and 2x + y = 0 is? The answer is X & sup2; + 6xy + Y & sup2; = 0
The one on the first floor didn't ask you to copy it

Let the point of two straight lines be (x, y), then | X-Y | / radical 2 = | 2x + y | / radical 5, and both sides are squared to get the equation x & sup2; + 6xy-y & sup2; = 0. Your answer is wrong

Given that the distance from the moving point P to the straight line x = - 5 and the fixed point a (1,0) are equal, the trajectory equation of the moving point P is obtained

According to the definition of parabola, the trajectory of point P is a parabola with a as the focus, x = - 5 as the Quasilinear, and the vertex is (- 2,0), P = 6
So the equation is Y & # 178; = 12 (x + 2)

If the equation x ^ 2Sin α + y ^ 2sin2 α = 1 represents an ellipse, then the value range of α is

When it is an ellipse, both coefficients must be greater than 0
That is, Sina > 0; sin2a > 0, and sin α ≠ sin2 α
The result should be {α| 2K π ＜ α ＜ (2k + 1 / 2) π, K ∈ Z, and α ≠ ± π / 3 + 2K π, K ∈ Z}
Because when the coefficients of X and y are the same, it becomes a circle!

It is known that the sum of the two right sides of a right triangle is equal to 8cm. Question: when the length of the two right sides is each cm, the area s (CM & S) of the right triangle
Maximum? What is the maximum?

Let one edge x, the other be (8-x), and the area be s
Then s = 1 / 2x (8-x) = - 1 / 2x & sup2; + 4x
We can find that the vertex of this function is (4,8)
So when x = 4, the maximum area is 8

The ratio of the two right sides of a right triangle is 8:5, and the length of the hypotenuse is 6.8cm. Then the area of the right triangle is equal to - square meters

√ (8 square meters + 5 square meters)
=√89
=9.43
The lengths of the two right angles are 6.8 * 8 / 9.43 = 5.769 cm and 6.8 * 5 / 9.43 = 3.601 cm respectively
The area of this right triangle
=5.769*3.601/2
=10.39 square centimeter

How many cm is the length of the other side of a right triangle
How to find the length of the other side

Assuming that both sides are right angles, the length of the other side = root 34cm
Suppose that one of the two sides is a right angle and the other is a bevel, then the length of the other side = 4cm

For a right triangle, the sum of the two right sides is 14, and the hypotenuse is 10. How many are the two right sides?
It's six and eight
But it takes a lot of steps. Please write it clearly,

According to the Pythagorean theorem, this is a group of Pythagorean numbers, so the two right angles are 6 and 8 respectively

If we know that the sum of the two right sides of a right triangle is 4 and the sum of the squares is 14, then its area is

Let the lengths of two right angles be x, y respectively
X+Y=4
X^2+Y^2=14
So xy = [(x + y) ^ 2 - (x ^ 2 + y ^ 2)] / 2 = 1
Then the area of right triangle is 1 / 2 * xy = 1 / 2

If the sum of the three sides of a right triangle is 1, what is the maximum area of the triangle
It's a process

Let three sides be a, B, C, and C be hypotenuse
a+b+c=1
a+b=1-c
It can be obtained from the mean inequality
ab