If f (x) = AX3 + 3x2 + 2 and f ′ (- 1) = 4, then the value of real number a is equal to______ ．

If f (x) = AX3 + 3x2 + 2 and f ′ (- 1) = 4, then the value of real number a is equal to______ ．

∵ f (x) = AX3 + 3x2 + 2, ∵ f ′ (x) = 3ax2 + 6x, f ′ (- 1) = 4, ∵ 3a-6 = 4, a = 103

If f (x) = ax ^ 3 + 3x ^ 2 + 2 and f '(- 1) = - 6, then the value of real number a is equal to

It's zero

Given that the function f (x) is equal to 1 / 3x ^ 3 ax B (A.B belongs to real number), we can obtain the minimum value - 3 / 4 where x is equal to 2, and find the second higher order Ti of F (x)

f '(x)=x^2+a,
It is known that f '(2) = 4 + a = 0, and f (2) = 8 / 3 + 2A + B = - 4 / 3,
The solution is a = - 4, B = 4,
Therefore, f (x) = 1 / 3 * x ^ 3-4x + 4