If the line ax + 2Y + 2 = 0 is parallel to the line 3x + ay + √ 6 = 0, what is the coefficient a

If the line ax + 2Y + 2 = 0 is parallel to the line 3x + ay + √ 6 = 0, what is the coefficient a

If they are parallel, the slopes are the same and not coincident, so a / 2 = 3 / A is the solution of A=+_ If a = √ 6, the answer is - √ 6

6. If the line ax-y + 2 = 0 and the line 3x-y-b = 0 are symmetric with respect to the line X-Y = 0, then what are a and B equal to

Method 1: inverse solution of the line y = ax + 2, x = (1 / a) y - (2 / a)
Exchange x, y to get y = (1 / a) x - (2 / a), which is the symmetric line of the line y = ax + 2
Like y = 3x-b, a = 1 / 3, B = 6
Method 2: take points (0,2) and (- 2 / A, 0) on the line y = ax + 2
If symmetric points (2,0) and (0, - 2 / a) are on the line y = 3x-b, a and B can also be obtained

When point P (x, y) moves on the line x-2y + 3 = 0, and point Q (AX + 2y-3,3x + by) also moves on the line, then a + B is equal to
RT

Without the special value method, Q satisfies the equation (AX + 2y-3) - 2 (3x + by) + 3 = 0 on the straight line, and then (a-6) x + 2y-2by = 0, x = 2y-3 is brought in to get the formula with only a, B, y, (2a-12 + 2-2b) y + 18-3a = 0, which means that when y takes any value, the formula holds, that is to say, 2a-12 + 2-2b = 0, 18-3a =